Chapter 3 ยท Parallel and Perpendicular Lines

Parallel, Perpendicular, and Skew Lines and Parallel Planes

Learn to tell parallel, perpendicular, and skew lines apart and to spot parallel planes, using only marks and stated facts, never the look of a figure.

14 min read

You already know how to find where lines and planes intersect. In this lesson, you will use that skill to name how two lines, or two planes, are related. Each name has an exact definition, and one word appears in several of them: two lines are coplanar when one plane contains both of them. Throughout this lesson, "two lines" means two different lines and "two planes" means two different planes.

Start with two lines in one plane. Parallel lines are two coplanar lines that do not intersect. A line goes on forever, so this includes places beyond the edge of a drawing. Matching arrow marks on two lines state that they are parallel. You write ABโ†”โˆฅCDโ†”\overleftrightarrow{AB} \parallel \overleftrightarrow{CD}, where ABโ†”\overleftrightarrow{AB} means line ABAB.

Perpendicular lines are two lines that intersect to form a right angle, which is an angle that measures exactly 90โˆ˜90^\circ. A small square at the intersection states a right angle. You write ABโ†”โŠฅAEโ†”\overleftrightarrow{AB} \perp \overleftrightarrow{AE}.

In the figure below, the arrows and the square state these two facts. The way the lines look does not.

A line is shown. The drawing is not to scale. Labelled elements: line A B; line C D; line A E; line F G. Marks: one arrow mark on line A B and line C D; a right-angle mark at line A B and line A E.
The arrows state that line ABAB is parallel to line CDCD. The square states a right angle at AA. No mark relates line AEAE and line FGFG.

Worked example

Reading marks in one plane

Given: all four lines in the figure lie in one plane. The figure is not drawn to scale, so use only that stated fact and the marks. Classify each pair: line ABAB and line CDCD; line ABAB and line AEAE; line AEAE and line FGFG.

  1. Line AB and line CD carry matching arrow marks, and those marks state that the lines are parallel. The reason is the marks, not the even gap you may see between the lines.

    ABโ†”โˆฅCDโ†”\overleftrightarrow{AB} \parallel \overleftrightarrow{CD}
  2. Line AB and line AE both pass through A, so they intersect there. The square mark at A states a right angle, so by the definition of perpendicular lines, they are perpendicular.

    ABโ†”โŠฅAEโ†”\overleftrightarrow{AB} \perp \overleftrightarrow{AE}
  3. Line AE and line FG may look parallel, but no arrow mark or stated fact says so. How they look is not a reason, so you cannot tell whether they intersect somewhere off the page. This pair stays unclassified.

Answer

Line ABAB is parallel to line CDCD, line ABAB is perpendicular to line AEAE, and the givens do not classify line AEAE and line FGFG.

Now leave the flat page. In space, two lines can miss each other without being parallel. Picture a straight, level road on a bridge above another straight, level road that runs in a different direction. On a flat map the roads seem to cross. Modeled as lines, they do not meet, and no single plane contains both.

Skew lines are two lines that are not coplanar. They cannot intersect, because by a theorem, two intersecting lines lie in exactly one plane. They cannot be parallel either, because the definition of parallel lines requires one plane that contains both lines.

Planes have a matching word. Parallel planes are two planes that do not intersect, so they share no point. If two planes share a point, they are not parallel, and by the postulate on intersecting planes, they meet in a line.

Key concept

Two questions sort any two lines

For two different lines, ask these questions in order.

1. Do they intersect? If yes, they are perpendicular when they form a right angle, and otherwise they are simply intersecting lines.

2. If they do not intersect, are they coplanar? If yes, they are parallel. If no, they are skew.

For two different planes, ask only whether they intersect. If they do not, they are parallel.

Answer only from marks and stated facts. A figure is not drawn to scale, so its look never answers a question. If the givens do not answer it, the pair stays unclassified.

The figure below is a flat sketch that stands for a see-through rectangular box. The front face is ABCDABCD and the back face is EFGHEFGH, with EE behind AA, FF behind BB, GG behind CC and HH behind DD. That makes ABFEABFE the top face, DCGHDCGH the bottom face, ADHEADHE the left face and BCGFBCGF the right face. Lines ABAB and EHEH are drawn past the box.

These facts are stated, so they are givens:

  • Each of the six faces is a rectangle. So each face lies in one plane, its neighboring sides form right angles, and its opposite sides are parallel.
  • Opposite faces lie in parallel planes.

The sketch is not drawn to scale, so read nothing else from it. A side of a face is a segment, and when you classify sides, you classify the lines that contain them. You can name a plane by three of its points that are not on one line. For example, plane ABCABC contains the front face.

A composite figure is shown. The drawing is not to scale. Labelled elements: polygon A B C D; polygon E F G H; line A B; line E H; segment D C; segment A D. Marks: one arrow mark on line A B and segment D C; a right-angle mark at line A B and segment A D.
A flat box sketch, not to scale. The arrows state that line ABAB and line DCDC are parallel, and the square states a right angle at AA. All other facts come from the text.

Worked example

Using stated facts about the box

Given: the stated box facts. The sketch is not drawn to scale, so do not use its look. Classify each pair: plane ABCABC and plane EFGEFG; plane ABCABC and plane ABFABF; line ABAB and line EFEF; line ABAB and line BFBF.

  1. Plane ABC contains the front face and plane EFG contains the back face. These are opposite faces, so the stated fact says that their planes are parallel.

    planeย ABCโˆฅplaneย EFG\text{plane } ABC \parallel \text{plane } EFG
  2. Plane ABC contains the front face and plane ABF contains the top face. Both planes contain A and B, so they intersect. By the definition of parallel planes, they are not parallel, and they meet in line AB.

    planeย ABCโˆฉplaneย ABF=ABโ†”\text{plane } ABC \cap \text{plane } ABF = \overleftrightarrow{AB}
  3. Line AB and line EF contain opposite sides of rectangle ABFE. The stated fact about faces says that opposite sides are parallel.

    ABโ†”โˆฅEFโ†”\overleftrightarrow{AB} \parallel \overleftrightarrow{EF}
  4. Line AB and line BF both pass through B, so they intersect. They contain neighboring sides of rectangle ABFE, so the stated fact gives a right angle at B, even though the sketch does not draw that corner square. By the definition of perpendicular lines, they are perpendicular.

    ABโ†”โŠฅBFโ†”\overleftrightarrow{AB} \perp \overleftrightarrow{BF}

Answer

Plane ABCABC is parallel to plane EFGEFG, plane ABCABC is not parallel to plane ABFABF, line ABAB is parallel to line EFEF, and line ABAB is perpendicular to line BFBF.

Worked example

Showing that two lines are skew

Given: the stated box facts. To show: line ABAB and line EHEH are skew. The two lines cross in the sketch, but that crossing is neither a mark nor a stated fact, and the sketch is not drawn to scale.

  1. First question: do the lines intersect? By the postulate that a line through two points of a plane lies in that plane, line AB lies in plane ABC and line EH lies in plane EFG. Those planes contain opposite faces, so they are parallel and share no point. So the lines do not intersect.

  2. Second question: are the lines coplanar? Suppose one plane contains both lines. Then that plane contains A, B, E and H.

  3. Sides AB and AE of rectangle ABFE form a right angle, so A, B and E are not on one line. By the postulate that exactly one plane passes through three points not on one line, the supposed plane must be plane ABF, the plane of the top face.

  4. H is a corner of the bottom face. The top and bottom faces are opposite, so their planes are parallel and share no point, by the definition of parallel planes. So H is not in plane ABF.

    Hโˆ‰planeย ABFH \notin \text{plane } ABF
  5. The supposed plane must contain H and must be plane ABF, which is impossible. So no plane contains both lines. They are not coplanar, so by the definition of skew lines, they are skew.

    ABโ†”ย andย EHโ†”ย areย skew\overleftrightarrow{AB} \text{ and } \overleftrightarrow{EH} \text{ are skew}

Answer

Line ABAB and line EHEH are skew, so they do not intersect, even though they cross in the sketch.

Here is the central idea. For two different lines, ask whether they intersect and then whether they are coplanar: lines that intersect at a right angle are perpendicular, coplanar lines that do not intersect are parallel, and lines that are not coplanar are skew. Two different planes that do not intersect are parallel. Base each answer on marks and stated facts, never on the look of a figure, because a figure is not drawn to scale. Next, you will meet transversals and classify the angle pairs they form.