Chapter 9 · Equations and inequalities

Model and Check Multiplication and Division Equations

Turn words and stories into one-step multiplication and division equations, solve and check them, match stories to equations, and find mistakes in worked solutions.

18 min read

An equation is a statement that two amounts are equal, such as 6x=1386x = 138. A variable is a letter, like xx, that stands for a number you do not know yet.

You already know how to solve equations like 6x=1386x = 138 and x4=2.5\frac{x}{4} = 2.5. In this lesson the equations come from words. You will write an equation from a sentence or a story, solve it and check it, pick the story that matches an equation, and find the mistake in someone else's work.

One idea runs through all four jobs: the equation must say exactly what the words say.

Some sentences name the operation for you. A product is the result of multiplying, and the numbers you multiply are its factors. A quotient is the result of dividing. The number being divided is the dividend, and the number you divide by is the divisor. A divisor is never zero, because dividing by zero has no meaning.

In sentences like the ones in the next table, the word is marks the equals sign. Order matters in division. The quotient of a number and 2.5 means the number divided by 2.5, not 2.5 divided by the number.

Sentences that name their operation
WordsWhat the words tell youEquation
The product of 8 and a number nn is 56.
Multiply 8 by nn. The result equals 56.
8n=568n = 56
A number yy divided by 5 is 7.
Divide yy by 5. The result equals 7.
y5=7\frac{y}{5} = 7
The quotient of a number qq and 2.5 is 6.
Divide qq by 2.5. The result equals 6.
q2.5=6\frac{q}{2.5} = 6
Two fifths of a number mm is 8.
A fraction of a number means multiply: 25\frac{2}{5} times mm equals 8.
25m=8\frac{2}{5}m = 8

A story does not always name the operation. You have to find the relationship yourself. Every story in this lesson is about equal groups, which are groups that all have the same size. Such a story links three quantities:

  • the number of groups,
  • the size of each group,
  • the total.

When nothing is left over, the number of groups times the size of each group equals the total. Turn that around and you get the division form: the total divided by the number of groups equals the size of each group. The number of groups is the divisor there, so it cannot be zero.

A story gives you two of the three quantities. The third is the unknown. Before you write an equation, say what your variable stands for and name its unit. For example: let bb be the number of batches, or let LL be the length in kilometers.

Key concept

The equation must tell the story

In an equal-groups story with nothing left over, the number of groups times the size of each group equals the total. An equation matches the story only when each quantity sits in its right place. To solve, do the same valid operation to both sides, so the two sides stay equal. Divide only by a number that is not zero. Then put your answer back into the original equation and back into the story. A correct exact answer makes the original equation true, and it must make sense for what the variable counts or measures.

number of groups×size of each group=total\text{number of groups} \times \text{size of each group} = \text{total}

Worked example

Writing equations from two stories

Write an equation for each story. Do not solve yet. Story 1: Notebooks cost 3 dollars each. Lena spends 42 dollars on notebooks. How many notebooks does she buy? Story 2: A trail is split into 4 equal sections. Each section is 2.5 kilometers long. How long is the trail?

  1. Story 1: name the unknown. Let n be the number of notebooks Lena buys. Each notebook is one group of 3 dollars. So the size of each group is 3 dollars, and the total is 42 dollars.

  2. Use the relationship: number of groups times size of each group equals the total. Here n groups of 3 dollars make 42 dollars. You may write 3n for n times 3, because the order of two factors never changes their product.

    3n=423n = 42
  3. Story 2: name the unknown. Let L be the length of the whole trail, in kilometers. This time the total is the unknown. The number of groups is 4 sections, and the size of each group is 2.5 kilometers.

  4. The story splits the total into 4 equal sections, so use the division form: total divided by number of groups equals size of each group. The divisor is 4, which is not zero.

    L4=2.5\frac{L}{4} = 2.5
  5. Read each equation back as a sentence. The first says n notebooks at 3 dollars each cost 42 dollars. The second says a trail of L kilometers, split into 4 equal sections, has sections of 2.5 kilometers. Each sentence matches its story.

Answer

Story 1 gives 3n=423n = 42, where nn is the number of notebooks. Story 2 gives L4=2.5\frac{L}{4} = 2.5, where LL is the length of the trail in kilometers.

Once the equation is written, you solve it the way you already know. Keep in mind why that method is safe, because you will need the reason when you look for mistakes. The two sides of an equation name the same number. If you do the same operation to both sides, you do it to that one number, so the results are still equal. You may multiply both sides by the same number. You may divide both sides by the same number, as long as that number is not zero.

Choose the operation that undoes what was done to the variable. Dividing by 3 undoes multiplying by 3. Multiplying by 4 undoes dividing by 4. Operations that undo each other like this are called inverse operations.

A story needs two more steps after you solve. Check your value in the original equation. A value that makes the equation true is called a solution. Then say what the solution means, with its unit. Try this on the two equations from the first example.

  • In 3n=423n = 42, the variable nn is multiplied by 3. Divide both sides by 3, which is not zero: n=42÷3=14n = 42 \div 3 = 14. Check: 3×14=423 \times 14 = 42. Lena buys 14 notebooks.
  • In L4=2.5\frac{L}{4} = 2.5, the variable LL is divided by 4. Multiply both sides by 4: L=2.5×4=10L = 2.5 \times 4 = 10. Check: 104=2.5\frac{10}{4} = 2.5. The trail is 10 kilometers long.

Worked example

Solving a story with decimals

One batch of granola bars uses 0.75 cup of oats. Sam uses exactly 4.5 cups of oats. How many batches does Sam make?

  1. Name the unknown. Let b be the number of batches Sam makes. Each batch is one group of 0.75 cup, and the total is 4.5 cups. Number of groups times size of each group equals the total.

    0.75b=4.50.75b = 4.5
  2. The variable b is multiplied by 0.75, so divide both sides by 0.75 to undo that. Both sides get the same operation, and 0.75 is not zero, so the two sides stay equal.

    0.75b0.75=4.50.75\frac{0.75b}{0.75} = \frac{4.5}{0.75}
  3. On the left, dividing by 0.75 undoes multiplying by 0.75 and leaves b. On the right, work out the quotient. Multiply the dividend and the divisor by 100. That does not change the quotient, and it gives 450 divided by 75. Since 75 times 6 is 450, the quotient is exactly 6.

    b=4.5÷0.75=450÷75=6b = 4.5 \div 0.75 = 450 \div 75 = 6
  4. Check in the original equation. The quotient is exact, so the quotient times the divisor must equal the dividend exactly. It does.

    6×0.75=4.56 \times 0.75 = 4.5
  5. Check the story. Six batches at 0.75 cup each use 4.5 cups of oats. A whole number of batches makes sense, so 6 answers the question.

Answer

Sam makes 66 batches of granola bars.

That check came out exactly equal because the quotient was exact. Not every answer is like that, so match your check to the kind of answer you have. The next table shows four cases. In it, the symbol ≈\approx means is about equal to.

A remainder is the whole amount left over when things cannot be shared out evenly. Compare the last two rows of the table. Ribbon can be cut, so each piece is 6.25 meters and nothing is left over. Stickers cannot be cut, so each friend gets 6 stickers and 1 sticker is left over. Do not turn a leftover into a fraction of something that cannot be split. Do not invent a leftover when the quantity can be split. So always ask what your variable counts or measures before you report an answer.

Match the check to the kind of answer
Kind of answerExampleHow to check
Exact quotient
4.5÷0.75=64.5 \div 0.75 = 6
Quotient times divisor equals the dividend exactly: 6×0.75=4.56 \times 0.75 = 4.5
Rounded quotient
10÷3≈3.3310 \div 3 \approx 3.33 (rounded to the nearest hundredth)
The check is only close: 3.33×3=9.993.33 \times 3 = 9.99, which is near 1010 but not equal to it
A quantity that can be split
25 meters of ribbon cut into 4 equal pieces: 6.25 meters each, nothing left over
Quotient times divisor equals the dividend exactly: 6.25×4=256.25 \times 4 = 25
Whole things that cannot be split, with some left over
25 stickers shared among 4 friends: 6 stickers each, 1 left over
Divisor times whole quotient, plus remainder: 4×6+1=254 \times 6 + 1 = 25

Now go the other way. Start with an equation and find its story. Two stories can use the very same numbers and still mean different things. So do not match by the numbers. Match by the relationship: ask which quantity is the total, which is the number of groups, and which is the size of each group.

It also helps to know when two forms mean the same thing. An expression is a group of numbers, variables and operations with no equals sign, such as 4x4x. Here xx can be any number. Two expressions are equivalent when they give the same value for every value the variable is allowed to take. For example, x×4x \times 4 and 4x4x are equivalent, because the order of two factors never changes a product. So a story that gives x×4=24x \times 4 = 24 matches the equation 4x=244x = 24.

Be careful with a single test. The expressions 4x4x and x4\frac{x}{4} both equal 00 when x=0x = 0. One matching value does not prove that two expressions are equivalent. At x=8x = 8 they give 3232 and 22. That one mismatch is enough to prove they are not equivalent.

Worked example

Three stories, one equation

Which story matches 2.5x=202.5x = 20? Story A: A tank holds 20 liters of water. It fills xx jugs that hold 2.5 liters each, with no water left over. Story B: xx liters of water are shared equally among 20 jugs. Each jug gets 2.5 liters. Story C: 2.5 liters of water are shared equally among 20 cups. Each cup gets xx liters.

  1. Read the equation as a sentence: 2.5 times x equals 20. So 20 is the total. The numbers 2.5 and x are the size of each group and the number of groups, in either order.

    2.5x=202.5x = 20
  2. Story A: x is the number of jugs. There are x groups of 2.5 liters, and the total is 20 liters. That is x times 2.5 equals 20. The expressions x times 2.5 and 2.5x are equivalent, so Story A matches.

    x×2.5=20x \times 2.5 = 20
  3. Story B: x is the total number of liters. It is divided among 20 jugs, and each jug gets 2.5 liters. Here 20 is the divisor, not the total, so this is a different equation.

    x20=2.5\frac{x}{20} = 2.5
  4. Story C: x is the number of liters in each cup. There are 20 groups of x liters, and the total is 2.5 liters. Here 2.5 is the total, not 20, so this is a different equation too.

    20x=2.520x = 2.5
  5. Test with the solution of the given equation. Divide both sides by 2.5, which is not zero, to leave x alone. Multiply the dividend and the divisor by 10 to get 200 divided by 25. Since 25 times 8 is 200, x is exactly 8.

    x=20÷2.5=200÷25=8x = 20 \div 2.5 = 200 \div 25 = 8
  6. Put 8 into each story. A: 8 jugs of 2.5 liters hold 20 liters, as the story says. B: 8 liters among 20 jugs gives 0.4 liter each, not 2.5. C: 20 cups of 8 liters hold 160 liters, not 2.5. One failed value rules out B and C. The matching relationship in Story A is what confirms A.

    8×2.5=208 \times 2.5 = 20

Answer

Story A matches 2.5x=202.5x = 20, because xx jugs of 2.5 liters each hold 20 liters in all. The solution x=8x = 8 means the tank fills 8 jugs.

The last job is to be the checker. When you look for a mistake, do not just redo the problem. Go through the work one line at a time and ask three questions:

  1. Does the equation match the words?
  2. Does each step do the same valid operation to both sides?
  3. Is the arithmetic right?

Then test the final value. If it is meant to be exact and it does not make the original equation true, something went wrong. Find the first line that does not follow from the line before it. Also ask whether the value makes sense in the story.

Worked example

Finding the mistake in Kai's work

One lap of a track is 34\frac{3}{4} mile. Kai ran exactly 12 miles. To find how many laps that is, Kai lets nn be the number of laps and writes three lines. Line 1: 34n=12\frac{3}{4}n = 12. Line 2: n=12×34n = 12 \times \frac{3}{4}. Line 3: n=9n = 9. Find the mistake and correct it.

  1. Check line 1 against the story. There are n laps, each lap is three fourths of a mile, and the total is 12 miles. Number of groups times size of each group equals the total, so line 1 is correct.

    34n=12\frac{3}{4}n = 12
  2. Check line 2. To leave n alone, the left side must be divided by three fourths, so the right side must be divided by three fourths as well, as shown. Kai multiplied the right side by three fourths instead. The two sides got different operations, so they are no longer equal. Line 2 holds the mistake.

    34n÷34=12÷34\frac{3}{4}n \div \frac{3}{4} = 12 \div \frac{3}{4}
  3. Confirm it with a check. The arithmetic in line 3 is right, because 12 times three fourths is 9. But 9 fails in the original equation: three fourths of 9 is 6.75, not 12. It fails in the story too, because 9 laps of less than a mile each cannot reach 12 miles.

    34×9=274=6.75\frac{3}{4} \times 9 = \frac{27}{4} = 6.75
  4. Correct the work. Divide both sides by three fourths, which is not zero. That leaves n alone on the left. On the right, dividing by three fourths gives the same result as multiplying by four thirds. Twelve times 4 is 48, and 48 divided by 3 is 16.

    n=12÷34=12×43=483=16n = 12 \div \frac{3}{4} = 12 \times \frac{4}{3} = \frac{48}{3} = 16
  5. Check the new value. The quotient 16 is exact, so the quotient times the divisor must equal the dividend exactly. Sixteen times three fourths is 48 fourths, which is 12. In the story, 16 laps is more than 12, as it should be when each lap is shorter than a mile.

    16×34=484=1216 \times \frac{3}{4} = \frac{48}{4} = 12

Answer

The mistake is in line 2: Kai multiplied 1212 by 34\frac{3}{4}, but both sides had to be divided by 34\frac{3}{4}. The correct solution is n=16n = 16, so Kai ran 16 laps.

Here is the idea to keep. An equation is a short way to tell a story, so each quantity must sit in its right place: the total, the number of groups and the size of each group. When you solve, do the same valid operation to both sides, and never divide by zero. When you finish, send your answer back to the original equation and to the story. Those same habits let you pick the story that fits an equation and find the line where someone's work went wrong.