Chapter 8 · Geometric figures and angle relationships

Triangle Inequality: Can Three Lengths Make a Triangle?

Find out whether three positive side lengths can form a true triangle by checking that the two shorter lengths add up to more than the longest.

10 min read

In the last lesson, you drew shapes that fit given conditions. Sometimes, though, the conditions cannot be met at all. Here is a question to keep in mind: can a triangle have sides of 3 cm, 4 cm and 10 cm?

A side joins two different corners, so its length is a distance greater than 0. That means every side length is a positive number, and a value of 0 or less cannot be a side at all. But being positive is not enough. In this lesson, you will learn a quick test, using only addition and a comparison, that tells you whether three positive lengths can be the sides of a triangle.

Start with what a side is. Each side of a triangle is the straight path between two corners, and a straight path is the shortest way to get from one point to another.

Now think about the longest side. The other two sides connect its two ends as well, but they go the long way around, through the third corner. That route leaves the straight path, so it is a detour, and a detour is longer than the straight path. So in a true triangle, the two shorter sides together must be longer than the longest side.

The table below puts numbers on this idea. The longest side is 10 cm in every row, and only the two shorter sides change. The first row is the opening question.

Three pairs of shorter sides with a longest side of 10 cm
Two shorter sidesTheir sum (cm)Sum compared with 10 cmWhat happens
3 cm and 4 cm
3+4=73 + 4 = 7
7<107 < 10
Together they are 3 cm too short to reach across the longest side, so they cannot meet. No triangle.
4 cm and 6 cm
4+6=104 + 6 = 10
10=1010 = 10
Together they reach across only by lying flat on the longest side. That makes a straight line, not a triangle.
5 cm and 7 cm
5+7=125 + 7 = 12
12>1012 > 10
Together they have 2 cm to spare, so they can meet at a corner away from the longest side. A triangle forms.

Key concept

The triangle inequality test

Let aa, bb and cc be three side lengths, all measured in the same unit and all positive (greater than 0). Name them so that a≤b≤ca \le b \le c. Then aa and bb are the two shorter lengths and cc is the longest.

The lengths form a nondegenerate triangle exactly when the two shorter lengths add up to more than the longest. An inequality is a comparison that says one amount is greater than or less than another, so this rule is called the triangle inequality.

  • a+b>ca + b > c: a nondegenerate triangle is possible.
  • a+b=ca + b = c: the sides lie flat in a straight line. This is degenerate, so there is no triangle.
  • a+b<ca + b < c: the two shorter sides cannot meet, so there is no triangle.
a+b>cwith 0<a≤b≤ca + b > c \quad \text{with } 0 < a \le b \le c

Why is one comparison enough? The detour idea is true for every side, not only the longest. So in a nondegenerate triangle, any two sides together are longer than the third side. That gives three comparisons: a+b>ca + b > c, a+c>ba + c > b and b+c>ab + c > a.

When the lengths are positive and named so that a≤b≤ca \le b \le c, two of these are true every time:

  • a+c>ba + c > b, because cc alone is at least as long as bb, and adding the positive length aa makes the sum greater than bb.
  • b+c>ab + c > a, because cc alone is at least as long as aa, and adding the positive length bb makes the sum greater than aa.

So a+b>ca + b > c is the only comparison that can fail. That is why you add the two shorter lengths. If two lengths tie for longest, either one can be cc, and the test works the same way.

Worked example

Lengths already in order

Can side lengths of 4 cm, 7 cm and 9 cm form a triangle?

  1. Check the conditions first. All three lengths are positive and all are in centimeters, so the test applies. They are already in order from least to greatest. The two shorter lengths are 4 cm and 7 cm, and the longest is 9 cm.

    0<4<7<90 < 4 < 7 < 9
  2. Add the two shorter lengths, 4 cm and 7 cm. These two sides together have to be longer than the longest side, so you need their total.

    4+7=114 + 7 = 11
  3. Compare the sum with the longest length. 11 cm is greater than 9 cm, so the two shorter sides have 2 cm to spare and can meet at a corner away from the longest side.

    11>911 > 9

Answer

Yes, side lengths of 4 cm, 7 cm and 9 cm form a nondegenerate triangle, because 4+7=114 + 7 = 11 and 11>911 > 9.

Worked example

Lengths out of order

Can side lengths of 14 cm, 5 cm and 8 cm form a triangle?

  1. All three lengths are positive and in centimeters, so the test applies. Put them in order from least to greatest. The two shorter lengths are 5 cm and 8 cm. The longest is 14 cm, even though it is listed first.

    0<5<8<140 < 5 < 8 < 14
  2. Add the two shorter lengths, 5 cm and 8 cm, because their total is what must be more than the longest length.

    5+8=135 + 8 = 13
  3. Compare the sum with the longest length. 13 cm is less than 14 cm, so the two shorter sides are 1 cm too short to reach across the longest side, and they cannot meet.

    13<1413 < 14

Answer

No, side lengths of 14 cm, 5 cm and 8 cm do not form a triangle, because 5+8=135 + 8 = 13 and 13<1413 < 14.

Worked example

A sum that only equals the longest side

Can side lengths of 6.5 m, 2.8 m and 3.7 m form a triangle?

  1. All three lengths are positive and in meters, so the test applies. In order, the two shorter lengths are 2.8 m and 3.7 m, and the longest is 6.5 m.

    0<2.8<3.7<6.50 < 2.8 < 3.7 < 6.5
  2. Add the two shorter lengths to get the total you will compare. The ones give 2 + 3 = 5 and the tenths give 0.8 + 0.7 = 1.5, so the total is 5 + 1.5 = 6.5.

    2.8+3.7=6.52.8 + 3.7 = 6.5
  3. Compare the sum with the longest length. The sum is equal to 6.5 m, not greater than it. The test needs a sum that is more than the longest length, so these lengths fail. The two shorter sides reach across only by lying flat on the longest side, which gives a straight, degenerate arrangement.

    6.5=6.56.5 = 6.5

Answer

No, side lengths of 6.5 m, 2.8 m and 3.7 m do not form a triangle, because 2.8+3.7=6.52.8 + 3.7 = 6.5 only equals the longest length. The sides make a flat, degenerate arrangement.

More checks with positive lengths in centimeters. With a tie, either tied length can be the longest.
Lengths in order (cm)Sum of the two shorter (cm)Longest (cm)ComparisonNondegenerate triangle?
6, 6, 6
6+6=126 + 6 = 12
6
12>612 > 6
Yes
3, 7, 7
3+7=103 + 7 = 10
7
10>710 > 7
Yes
2, 2, 5
2+2=42 + 2 = 4
5
4<54 < 5
No, the two shorter sides cannot meet
3, 3, 6
3+3=63 + 3 = 6
6
6=66 = 6
No, flat and degenerate
2.5, 2.6, 5
2.5+2.6=5.12.5 + 2.6 = 5.1
5
5.1>55.1 > 5
Yes, even 0.1 cm to spare is enough

Takeaway: To decide whether three positive lengths in the same unit form a nondegenerate triangle, add the two shorter lengths and compare the sum with the longest. If the sum is more than the longest, a triangle is possible. If the sum equals the longest, the sides lie flat in a straight line. If the sum is less, the two shorter sides cannot meet. In those last two cases, there is no triangle.

Next, you will draw triangles from three given side lengths and from given angle measures.