Chapter 2 ยท Operations with rational numbers

Signs First: Multiplying and Dividing Decimals

Learn why counting negative numbers gives the sign of a product or quotient of nonzero numbers, then multiply and divide positive and negative decimals.

16 min read

You already multiply and divide integers such as โˆ’3-3 and 44. You know that (โˆ’3)(4)=โˆ’12(-3)(4) = -12 and that (โˆ’12)รท(โˆ’4)=3(-12) \div (-4) = 3. Good news: the same reasoning about signs works for decimals such as โˆ’2.5-2.5 and 0.40.4, and this lesson shows you why. Decimals like these are rational numbers: numbers you can write as a fraction of two integers with a nonzero denominator (the bottom number). For example, โˆ’2.5=โˆ’2510-2.5 = \frac{-25}{10}.

A few words will help. A product is the result of multiplying, and the numbers you multiply are its factors. A quotient is the result of dividing. The number you divide is the dividend, and the number you divide by is the divisor, which must not be 00.

A nonzero answer has two parts: a sign (positive or negative) and a size. The size is the absolute value, which is the number's distance from 00, so โˆฃโˆ’2.5โˆฃ=2.5\lvert -2.5 \rvert = 2.5. You will find the sign first and the size second.

Start with one fact: multiplying a number by โˆ’1-1 gives its opposite. Two numbers are opposites when they add to 00, like 2.52.5 and โˆ’2.5-2.5.

Here is why, using 2.52.5. Add the products (โˆ’1)(2.5)(-1)(2.5) and (1)(2.5)(1)(2.5). The distributive property works for negative numbers just as it does for positive numbers. It lets you add โˆ’1-1 and 11 first and then multiply the sum by 2.52.5:

(โˆ’1)(2.5)+(1)(2.5)=(โˆ’1+1)(2.5)=(0)(2.5)=0(-1)(2.5) + (1)(2.5) = (-1 + 1)(2.5) = (0)(2.5) = 0

The two products add to 00, so they are opposites. Since (1)(2.5)=2.5(1)(2.5) = 2.5, the other product is (โˆ’1)(2.5)=โˆ’2.5(-1)(2.5) = -2.5. These steps do not depend on the value 2.52.5. Start with โˆ’2.5-2.5 and they show that (โˆ’1)(โˆ’2.5)(-1)(-2.5) is the opposite of โˆ’2.5-2.5, which is 2.52.5.

Now look at what a negative factor does. Every negative number is โˆ’1-1 times its absolute value. For example, โˆ’0.4=(โˆ’1)(0.4)-0.4 = (-1)(0.4). So each negative factor puts one โˆ’1-1 into the product, and each โˆ’1-1 flips the product to its opposite.

You may multiply factors in any order, so you can bring the โˆ’1-1 factors together:

(โˆ’1.5)(โˆ’0.4)=(โˆ’1)(1.5)(โˆ’1)(0.4)=(โˆ’1)(โˆ’1)(1.5)(0.4)=(1)(0.6)=0.6(-1.5)(-0.4) = (-1)(1.5)(-1)(0.4) = (-1)(-1)(1.5)(0.4) = (1)(0.6) = 0.6

Here (โˆ’1)(โˆ’1)=1(-1)(-1) = 1 because the opposite of โˆ’1-1 is 11. When no factor is 00, the product of the absolute values is positive. One flip makes the product negative, and a second flip makes it positive again. So for nonzero factors, the number of negative factors decides the sign.

Quotients follow the same pattern because division undoes multiplication, as long as the divisor is not 00. For example, (โˆ’36)รท5(-36) \div 5 asks: what number times 55 gives โˆ’36-36? A positive number times 55 is positive, and 00 times 55 is 00, so the answer must be negative. Since 36รท5=7.236 \div 5 = 7.2, try โˆ’7.2-7.2. It works: (โˆ’7.2)(5)=โˆ’36(-7.2)(5) = -36. So (โˆ’36)รท5=โˆ’7.2(-36) \div 5 = -7.2, a rational number written as a decimal.

With two negative numbers the quotient is positive: (โˆ’36)รท(โˆ’5)=7.2(-36) \div (-5) = 7.2, because (7.2)(โˆ’5)=โˆ’36(7.2)(-5) = -36.

As long as the divisor is not 00, a single negative sign can sit in the dividend, in the divisor, or in front of the whole quotient. The value is the same each time:

โˆ’365=36โˆ’5=โˆ’365=โˆ’7.2\frac{-36}{5} = \frac{36}{-5} = -\frac{36}{5} = -7.2

Key concept

Sign from the count, size from the absolute values

For a product or quotient in which every number is nonzero:

  • Sign: count the negative numbers. An odd count gives a negative result. An even count (including none) gives a positive result.
  • Size: multiply or divide the absolute values.

Zero has its own rules, so look for it first. Any zero factor makes a product 00. Zero divided by a nonzero number is 00. Division by 00 is undefined, which means it has no value, so a divisor is never 00.

Products and quotients in which no number is zero
ExpressionNegative numbersOdd or even countSign of the resultValue
(โˆ’2.5)(4)(-2.5)(4)
1
odd
negative
โˆ’10-10
(โˆ’2.5)(โˆ’4)(-2.5)(-4)
2
even
positive
1010
(โˆ’7.2)รท0.9(-7.2) \div 0.9
1
odd
negative
โˆ’8-8
(โˆ’7.2)รท(โˆ’0.9)(-7.2) \div (-0.9)
2
even
positive
88
(โˆ’1.5)(โˆ’2)(โˆ’0.4)(-1.5)(-2)(-0.4)
3
odd
negative
โˆ’1.2-1.2
(1.5)(2)(0.4)(1.5)(2)(0.4)
0
even
positive
1.21.2

Worked example

Find the sign before you compute

Divide the product (โˆ’0.5)(4)(โˆ’1.2)(-0.5)(4)(-1.2) by โˆ’3-3. Is the result positive, negative, or zero? Decide first, then check by computing.

  1. Look for zero first, because the counting rule needs every number to be nonzero. None of the three factors is 0, so the product is not 0. The divisor is not 0, so the quotient is defined.

    (โˆ’0.5)(4)(โˆ’1.2)โˆ’3\frac{(-0.5)(4)(-1.2)}{-3}
  2. Count the negative numbers. Two of the three factors are negative, and the divisor is negative too. The count is 3.

    (โˆ’0.5),(โˆ’1.2),(โˆ’3)(-0.5),\quad (-1.2),\quad (-3)
  3. Use the count. 3 is odd, so the result is negative. Here is the reason: the two negative factors flip the product twice, so the product is positive, and dividing by the negative divisor flips the sign one more time.

  4. Check by computing from left to right. The results are negative, then positive, then negative, because the sign flips at each negative number.

    (โˆ’0.5)(4)=โˆ’2,(โˆ’2)(โˆ’1.2)=2.4,2.4รท(โˆ’3)=โˆ’0.8(-0.5)(4) = -2, \quad (-2)(-1.2) = 2.4, \quad 2.4 \div (-3) = -0.8

Answer

The result is negative, because no number is 00 and there are 3 negative numbers, which is an odd count. Its value is โˆ’0.8-0.8.

Now you can find the whole answer. To multiply or divide positive and negative decimals, use three steps:

  1. Sign. If any number is 00, use the zero rules. If no number is 00, count the negative numbers to get the sign.
  2. Size. Multiply or divide the absolute values, which are positive decimals.
  3. Combine. Put the sign and the size together.

To find the size, change the decimals into whole numbers. In a product, write each decimal as a whole number divided by a power of ten (1010, 100100, 10001000 and so on). For example, 2.4=24รท102.4 = 24 \div 10. In a quotient, multiply the dividend and the nonzero divisor by the same power of ten. This is like writing an equivalent fraction: the quotient stays the same, just as 6รท26 \div 2 and 60รท2060 \div 20 are both 33.

Worked example

Multiply two negative decimals

Find (โˆ’2.4)(โˆ’0.35)(-2.4)(-0.35).

  1. Find the sign. Neither factor is 0, so you can count. Both factors are negative, which makes a count of 2. An even count gives a positive product.

  2. Find the size with the absolute values 2.4 and 0.35. Write each one as a whole number divided by a power of ten: 2.4 is 24 tenths and 0.35 is 35 hundredths.

    2.4=24รท10,0.35=35รท1002.4 = 24 \div 10, \qquad 0.35 = 35 \div 100
  3. Multiply the whole numbers. Split 35 into 30 and 5 so that each part is easy to multiply by 24.

    24ร—35=24ร—30+24ร—5=720+120=84024 \times 35 = 24 \times 30 + 24 \times 5 = 720 + 120 = 840
  4. Divide by 10 times 100, which is 1000, because tenths times hundredths are thousandths. Dividing by 1000 shifts each digit three places to the right, and the final zero does not change the value.

    2.4ร—0.35=840รท1000=0.840=0.842.4 \times 0.35 = 840 \div 1000 = 0.840 = 0.84
  5. Put the positive sign and the size 0.84 together. Check with an estimate: 0.35 is close to one third, and one third of 2.4 is 0.8, which is close to 0.84.

    (โˆ’2.4)(โˆ’0.35)=0.84(-2.4)(-0.35) = 0.84

Answer

The product (โˆ’2.4)(โˆ’0.35)(-2.4)(-0.35) is 0.840.84. It is positive because no factor is 00 and the 2 negative factors make an even count.

Worked example

Divide a negative decimal by a positive decimal

One evening the outdoor temperature changes by โˆ’7.65-7.65 degrees Celsius over 4.54.5 hours. The change is negative because the temperature goes down. The temperature falls by the same amount every hour. What is the change in temperature for one hour?

  1. Write the quotient. Because the temperature falls by the same amount every hour, the change for one hour is the total change in degrees Celsius divided by the number of hours. The divisor 4.5 is not 0, so the quotient is defined.

    (โˆ’7.65)รท4.5(-7.65) \div 4.5
  2. Find the sign. Neither number is 0, and exactly 1 of them is negative. An odd count gives a negative quotient.

  3. Find the size with the absolute values 7.65 and 4.5. Multiply both by 10 so that the divisor is a whole number. Multiplying the dividend and the divisor by the same nonzero number does not change the quotient.

    7.65รท4.5=(7.65ร—10)รท(4.5ร—10)=76.5รท457.65 \div 4.5 = (7.65 \times 10) \div (4.5 \times 10) = 76.5 \div 45
  4. Divide 76.5 by 45. One 45 fits into 76 and leaves 31 ones. Those 31 ones and the 5 tenths make 315 tenths. Since 45 times 7 is 315, the next digit is 7 tenths.

    76.5รท45=1.776.5 \div 45 = 1.7
  5. Put the negative sign and the size 1.7 together. Then check: because the divisor is not 0, the quotient times the divisor must give back the dividend. 17 times 45 is 765, and tenths times tenths are hundredths, so 1.7 times 4.5 is 7.65. One negative factor makes that product negative.

    (โˆ’7.65)รท4.5=โˆ’1.7,(โˆ’1.7)(4.5)=โˆ’7.65(-7.65) \div 4.5 = -1.7, \qquad (-1.7)(4.5) = -7.65

Answer

The temperature changes by โˆ’1.7-1.7 degrees Celsius for each hour, which means it falls 1.71.7 degrees Celsius every hour.

The big idea: find the sign and the size of a product or quotient separately. Look for 00 first: any zero factor makes a product 00, zero divided by a nonzero number is 00, and you never divide by 00. When every number is nonzero, count the negative numbers. An odd count gives a negative result and an even count gives a positive result, because each negative number flips the result to its opposite. Then multiply or divide the absolute values to get the size.

Next, you will use the same ideas to multiply and divide positive and negative fractions, and you will apply properties of operations, such as the distributive property, to rational numbers.