Chapter 4 · Percents

Percent of Change and New Amounts

Compare a change with the original amount to find a percent of increase or decrease, then use a percent of change to find the new amount.

16 min read

One playlist grows from 2020 songs to 2525 songs. Another grows from 200200 songs to 205205 songs. Each playlist gained 55 songs, yet the first change feels much bigger. That is because 55 songs is a large share of 2020 songs but a small share of 200200 songs.

A percent of change puts a number on that idea. It tells you how large a change is compared with the amount you started with. In this lesson you will find a percent of change, and then use a percent of change to find a new amount.

Every problem in this lesson has three quantities, all measured in the same unit:

  • The original amount is the amount before the change. In this lesson it is always a positive number.
  • The new amount is the amount after the change.
  • The amount of change is the difference between them: how much was gained or lost. To find it, subtract the smaller amount from the larger one.

If the new amount is greater than the original amount, the change is an increase. If the new amount is less than the original amount, the change is a decrease.

You already know that a percent is a rate per 100100 of a stated positive whole, and that part=percent×whole\text{part} = \text{percent} \times \text{whole}. For a percent of change, the whole is the original amount and the part is the amount of change.

Try it with the first playlist. The original amount is 2020 songs, which is positive, and the new amount is 2525 songs. The amount of change is 25−20=525 - 20 = 5 songs. Write the change as a fraction of the original amount, then scale it to a rate per 100100:

520=5×520×5=25100=25%\frac{5}{20} = \frac{5 \times 5}{20 \times 5} = \frac{25}{100} = 25\%

Multiplying the numerator and the denominator by 55 keeps the ratio the same, so the first playlist grew by 25%25\%. That is its percent of increase.

The second playlist also changed by 55 songs, but its original amount is 200200 songs: 5200=2.5100=2.5%\frac{5}{200} = \frac{2.5}{100} = 2.5\%. Dividing the numerator and the denominator by 22 keeps the ratio the same, so its percent of increase is only 2.5%2.5\%.

Key concept

Percent of change compares the change to the original

A percent of change is the amount of change written as a rate per 100100 of the original amount. The original amount is the whole, so it must be positive, and it is the number you divide by, never the new amount. Multiplying by 100%100\%, which equals 11, rewrites the result of the division as a percent without changing its value. Call it a percent of increase when the new amount is greater than the original amount, and a percent of decrease when the new amount is less than the original amount.

percent of change=amount of changeoriginal amount×100%\text{percent of change} = \frac{\text{amount of change}}{\text{original amount}} \times 100\%

Worked example

Find a percent of decrease

A water tank holds 250250 liters on Monday. On Friday it holds 190190 liters. Find the percent of change in the amount of water, and say whether it is an increase or a decrease.

  1. Name the quantities. Monday comes first, so the original amount is 250 liters, which is positive. The new amount is 190 liters. The new amount is less than the original amount, so the change is a decrease.

    190<250190 < 250
  2. Find the amount of change. Subtract the smaller amount from the larger one to see how many liters the tank lost.

    250−190=60250 - 190 = 60
  3. Divide the amount of change by the original amount, because the positive original 250 liters is the whole you compare with. Dividing both numbers by 10 and then multiplying both by 4 keeps the ratio the same and gives a denominator of 100.

    60250=625=24100=0.24\frac{60}{250} = \frac{6}{25} = \frac{24}{100} = 0.24
  4. Write the decimal as a percent. Since 100% equals 1, multiplying by 100% does not change the value. It only rewrites 0.24 as a rate per 100.

    0.24×100%=24%0.24 \times 100\% = 24\%

Answer

The amount of water decreased by 24%24\%. The tank lost 6060 liters, and 6060 liters is 24%24\% of the original 250250 liters.

Now reverse the question. You know the positive original amount and the percent of change, and you want the new amount.

The percent of change tells you what part of the original amount is added or taken away. So first find the amount of change with part=percent×whole\text{part} = \text{percent} \times \text{whole}, using the original amount as the whole. Then:

  • after an increase, add the amount of change to the original amount;
  • after a decrease, subtract the amount of change from the original amount.

Suppose a game score of 8080 points increases by 15%15\%. Since 15%15\% means 1515 per 100100, write it as 0.150.15. The amount of change is 0.15×80=120.15 \times 80 = 12 points, so the new amount is 80+12=9280 + 12 = 92 points.

You can also get there in one step. The original amount is 100%100\% of itself, so after a 15%15\% increase you have 100%+15%=115%100\% + 15\% = 115\% of it:

80+0.15×80=(1+0.15)×80=1.15×80=9280 + 0.15 \times 80 = (1 + 0.15) \times 80 = 1.15 \times 80 = 92

Here is why that works. The original amount is 1×801 \times 80 and the amount of change is 0.15×800.15 \times 80. Each is a number times 8080, so you can add the two numbers first, 1+0.15=1.151 + 0.15 = 1.15, and then multiply by 8080 once. That is the distributive property at work. The number 1.151.15 is the multiplier: the number you multiply the original amount by to get the new amount. It is 115%115\% written as a decimal.

In general, let rr stand for the percent of change written as a decimal, such as r=0.15r = 0.15 for 15%15\%. For a positive original amount:

  • after an increase, new amount=original amount×(1+r)\text{new amount} = \text{original amount} \times (1 + r);
  • after a decrease, new amount=original amount×(1−r)\text{new amount} = \text{original amount} \times (1 - r).

An amount that cannot go below zero can lose at most 100%100\% of itself, so for a decrease of such an amount, rr is at most 11.

Multipliers for a positive original amount of 80 points
Percent of changePercent of the original you end withMultiplierNew amount (points)
15%15\% increase
100%+15%=115%100\% + 15\% = 115\%
1.151.15
1.15×80=921.15 \times 80 = 92
15%15\% decrease
100%−15%=85%100\% - 15\% = 85\%
0.850.85
0.85×80=680.85 \times 80 = 68
5%5\% increase
100%+5%=105%100\% + 5\% = 105\%
1.051.05
1.05×80=841.05 \times 80 = 84
40%40\% decrease
100%−40%=60%100\% - 40\% = 60\%
0.600.60
0.60×80=480.60 \times 80 = 48

Worked example

Find the new amount after an increase

A school club has 6060 members. Its membership increases by 35%35\%. How many members does the club have now?

  1. The original amount is 60 members. It is positive, and it is the whole for this percent. Write the percent of increase as a decimal, because 35% means 35 per 100.

    35%=35100=0.3535\% = \frac{35}{100} = 0.35
  2. Find the amount of change. It is 35% of the original amount, so multiply 0.35 by the original 60 members. Since 0.35 is 35 hundredths, multiply 35 by 60 and divide by 100.

    0.35×60=35×60100=2100100=210.35 \times 60 = \frac{35 \times 60}{100} = \frac{2100}{100} = 21
  3. The change is an increase, so add it to the original amount. The club keeps its 60 members and gains 21 more.

    60+21=8160 + 21 = 81
  4. Check with the multiplier. The club ends with 100% + 35% = 135% of its original membership, so multiplying the original amount by 1.35 must give the same new amount.

    (1+0.35)×60=1.35×60=81(1 + 0.35) \times 60 = 1.35 \times 60 = 81

Answer

After a 35%35\% increase, the club has 8181 members.

Worked example

Find the new amount after a decrease

A bag of trail mix has a mass of 400400 grams. The company decreases the mass by 12.5%12.5\%. What is the new mass of the bag?

  1. The original amount is 400 grams, which is positive and is the whole. Write the percent of decrease as a decimal.

    12.5%=12.5100=0.12512.5\% = \frac{12.5}{100} = 0.125
  2. A decrease takes part of the original amount away, so subtract from 1 to get the multiplier. The bag keeps 100% - 12.5% = 87.5% of its original mass.

    1−0.125=0.8751 - 0.125 = 0.875
  3. Multiply the original amount by the multiplier to get the new amount in grams. Since 400 is 100 times 4, multiply 0.875 by 100 first, then by 4.

    0.875×400=87.5×4=3500.875 \times 400 = 87.5 \times 4 = 350
  4. Check by finding the percent of change. The amount of change is 400 - 350 = 50 grams. Divide it by the original 400 grams, not by the new 350 grams.

    400−350400=50400=12.5100=12.5%\frac{400 - 350}{400} = \frac{50}{400} = \frac{12.5}{100} = 12.5\%

Answer

After a 12.5%12.5\% decrease, the new mass of the bag is 350350 grams.

The takeaway: a percent of change always measures the change against the positive original amount, never the new amount. To find it, divide the amount of change by the original amount and write the result as a percent. To go the other way, find that percent of the original amount, then add it for an increase or subtract it for a decrease. In one step, multiply the original amount by 1+r1 + r for an increase or by 1−r1 - r for a decrease, where rr is the percent of change written as a decimal.

Next, you will work backward to find the original amount before a percent change, and you will solve percent of change word problems.