Chapter 6 Β· Proportional relationships, lines, and slope

Finding and Fixing Slope Errors

Learn to check slope work step by step, find exactly where it goes wrong, and correct it, from mixed point order to lost negative signs.

13 min read

A slope calculation is a short chain of small steps, and any one of them can go wrong. In this lesson you are the checker. You read slope work that someone else wrote, find the exact step that went wrong, explain why it is wrong, and fix it.

First, recall what the number means. The slope of a line that is not vertical is the change in yy divided by the change in xx between two different points on the line. A change is the second value minus the first, so it can be negative. The slope tells you how many units yy changes each time xx goes up by 11. It is the same for every pair of different points on that line, so there is exactly one right answer to check against.

Key concept

What correct slope work does

Take two different points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) with x1β‰ x2x_1 \neq x_2, and let mm stand for the slope of the line through them. Correct work with the slope formula does four things:

  • It puts the change in yy on top and the change in xx on the bottom.
  • It uses the two points in the same order on top and on the bottom.
  • It keeps the sign of every coordinate when it subtracts.
  • It finishes the division correctly.

A slip in any one of these can change the answer. If x1=x2x_1 = x_2, the points lie on a vertical line and the bottom would be 00. Division by zero is undefined, so a vertical line has undefined slope.

m=y2βˆ’y1x2βˆ’x1forΒ x1β‰ x2m = \frac{y_2 - y_1}{x_2 - x_1} \quad \text{for } x_1 \neq x_2

Here are five attempts to find the slope of the line through (βˆ’2,5)(-2, 5) and (4,βˆ’7)(4, -7). Two are correct. For the other three, decide which item in the list above each one breaks before you read the last column.

Five attempts at the same slope
AttemptWorkWhat happened
A
βˆ’7βˆ’54βˆ’(βˆ’2)=βˆ’126=βˆ’2\frac{-7 - 5}{4 - (-2)} = \frac{-12}{6} = -2
Correct: change in yy over change in xx, same order, signs kept.
B
5βˆ’(βˆ’7)βˆ’2βˆ’4=12βˆ’6=βˆ’2\frac{5 - (-7)}{-2 - 4} = \frac{12}{-6} = -2
Correct: the other order on top and on the bottom. Both changes switch sign, so the value is the same.
C
4βˆ’(βˆ’2)βˆ’7βˆ’5=6βˆ’12=βˆ’12\frac{4 - (-2)}{-7 - 5} = \frac{6}{-12} = -\frac{1}{2}
Upside down: this divides the change in xx by the change in yy.
D
βˆ’7βˆ’5βˆ’2βˆ’4=βˆ’12βˆ’6=2\frac{-7 - 5}{-2 - 4} = \frac{-12}{-6} = 2
Mixed order: the top puts (4,βˆ’7)(4, -7) first, but the bottom puts (βˆ’2,5)(-2, 5) first.
E
βˆ’7βˆ’54βˆ’2=βˆ’122=βˆ’6\frac{-7 - 5}{4 - 2} = \frac{-12}{2} = -6
Sign slip: the bottom should be 4βˆ’(βˆ’2)=64 - (-2) = 6, but the negative sign was dropped.

To check slope work, do not just scan it for something that looks odd. Rebuild it and compare.

  1. Find the true slope yourself from the exact coordinates: change in yy over change in xx, both as second point minus first point. Divide only if the change in xx is not 00. If it is 00, the line is vertical and the slope is undefined.
  2. Read the given work from the start. It is a chain of expressions joined by equals signs. Work out the value of each expression.
  3. Stop at the first expression whose value is not the true slope. Every expression in correct work is the slope written another way, so this is where the work went wrong. If it is the very first expression, the setup is wrong. If it is a later one, the step into it changed the value.
  4. Name the error and correct the work from there.

You can also test a final answer directly, with the move you already use to find a missing coordinate. For two points with different xx-values, the slope times the change in xx equals the change in yy. So a number mm is the correct slope exactly when starting at y1y_1 and adding mm times the change in xx lands on y2y_2:

y1+m (x2βˆ’x1)=y2whenΒ x1β‰ x2y_1 + m\,(x_2 - x_1) = y_2 \quad \text{when } x_1 \neq x_2

Worked example

Checking Kai's work

Kai finds the slope of the line through (2,9)(2, 9) and (6,1)(6, 1). He writes m=9βˆ’16βˆ’2=84=2m = \frac{9 - 1}{6 - 2} = \frac{8}{4} = 2. Find the error and correct it.

  1. Find the true slope. Call (2,9)(2, 9) the first point and (6,1)(6, 1) the second. The change in yy is 1βˆ’9=βˆ’81 - 9 = -8 and the change in xx is 6βˆ’2=46 - 2 = 4. The change in xx is not 00, so you can divide.

    m=1βˆ’96βˆ’2=βˆ’84=βˆ’2m = \frac{1 - 9}{6 - 2} = \frac{-8}{4} = -2
  2. Read Kai's work from the start. His first expression has the value 84=2\frac{8}{4} = 2, not βˆ’2-2, so the error is already in the setup. A second clue: from (2,9)(2, 9) to (6,1)(6, 1), xx goes up while yy goes down, so the slope must be negative.

    9βˆ’16βˆ’2=84=2β‰ βˆ’2\frac{9 - 1}{6 - 2} = \frac{8}{4} = 2 \neq -2
  3. Name the error. On top, 9βˆ’19 - 1 puts (2,9)(2, 9) first. On the bottom, 6βˆ’26 - 2 puts (6,1)(6, 1) first. Kai mixed the order of the points. Reversing only one of the two subtractions changes its sign, so the whole fraction is multiplied by βˆ’1-1. That turned βˆ’2-2 into 22.

    9βˆ’1=βˆ’(1βˆ’9)9 - 1 = -(1 - 9)
  4. Test the corrected slope. Start at y1=9y_1 = 9 and add mm times the change in xx. You land on y2=1y_2 = 1, so βˆ’2-2 is correct.

    9+(βˆ’2)(6βˆ’2)=9+(βˆ’2)(4)=9βˆ’8=19 + (-2)(6 - 2) = 9 + (-2)(4) = 9 - 8 = 1

Answer

Kai used the points in mixed order, so he got the opposite of the true slope. The slope of the line through (2,9)(2, 9) and (6,1)(6, 1) is βˆ’2-2.

Worked example

Checking Maya's work

Maya finds the slope of the line through (βˆ’3,1)(-3, 1) and (5,7)(5, 7). She writes m=7βˆ’15βˆ’(βˆ’3)=65βˆ’3=62=3m = \frac{7 - 1}{5 - (-3)} = \frac{6}{5 - 3} = \frac{6}{2} = 3. Find the error and correct it.

  1. Find the true slope. The change in yy is 7βˆ’1=67 - 1 = 6. The change in xx is 5βˆ’(βˆ’3)5 - (-3). From βˆ’3-3 you go up 33 to reach 00, then 55 more to reach 55, so the change is 88. In symbols, subtracting βˆ’3-3 is the same as adding 33. The change in xx is not 00, so you can divide.

    m=7βˆ’15βˆ’(βˆ’3)=65+3=68=34m = \frac{7 - 1}{5 - (-3)} = \frac{6}{5 + 3} = \frac{6}{8} = \frac{3}{4}
  2. Check Maya's first expression. It matches the correct setup and has the value 68=34\frac{6}{8} = \frac{3}{4}. So far her work is correct: change in yy on top, change in xx on the bottom, same order.

  3. Check her second expression. Its value is 62=3\frac{6}{2} = 3, not 34\frac{3}{4}, so the step into this expression changed the value. The top is right, because 7βˆ’1=67 - 1 = 6. On the bottom, 5βˆ’(βˆ’3)5 - (-3) became 5βˆ’35 - 3. Maya dropped the negative sign of βˆ’3-3.

    65βˆ’3=62=3β‰ 34\frac{6}{5 - 3} = \frac{6}{2} = 3 \neq \frac{3}{4}
  4. Test the corrected slope. Start at y1=1y_1 = 1 and add mm times the change in xx, which is 88. You land on y2=7y_2 = 7, so 34\frac{3}{4} is correct.

    1+34β‹…8=1+244=1+6=71 + \frac{3}{4} \cdot 8 = 1 + \frac{24}{4} = 1 + 6 = 7

Answer

Maya's setup is correct, but she changed 5βˆ’(βˆ’3)5 - (-3) into 5βˆ’35 - 3 and lost the negative sign. The slope of the line through (βˆ’3,1)(-3, 1) and (5,7)(5, 7) is 34\frac{3}{4}.

Three points on one line
xyy divided by x
11
55
55
22
77
3.53.5
44
1111
2.752.75

Worked example

Checking Dev's work

The table above lists three points on one line: (1,5)(1, 5), (2,7)(2, 7) and (4,11)(4, 11). Dev looks at the first row and writes that the slope is yx=51=5\frac{y}{x} = \frac{5}{1} = 5. Find the error and correct it.

  1. Find the true slope from two rows, (1,5)(1, 5) and (2,7)(2, 7). The change in xx is 2βˆ’1=12 - 1 = 1, which is not 00, so you can divide.

    m=7βˆ’52βˆ’1=21=2m = \frac{7 - 5}{2 - 1} = \frac{2}{1} = 2
  2. Read Dev's work. Its value is 55, not 22, so his setup is wrong. He divided one point's yy-value by its xx-value. He never found a change in yy or a change in xx.

    51=5β‰ 2\frac{5}{1} = 5 \neq 2
  3. See why the shortcut fails here. This line has one slope, but the last column of the table gives a different number in each row. Dividing yy by xx (with x≠0x \neq 0) gives the slope only for a proportional relationship, y=kxy = kx with kk a constant, whose line passes through the origin. This line is straight, but the relationship is not proportional.

    51=5,72=3.5,114=2.75\frac{5}{1} = 5, \quad \frac{7}{2} = 3.5, \quad \frac{11}{4} = 2.75
  4. Test the slope 22 on a different pair of rows, (1,5)(1, 5) and (4,11)(4, 11). This is a fair test because the slope is the same between any two different points on a line that is not vertical. Start at 55 and add 22 times the change in xx. You land on 1111.

    5+2(4βˆ’1)=5+2(3)=5+6=115 + 2(4 - 1) = 5 + 2(3) = 5 + 6 = 11

Answer

Dev divided a single yy-value by its xx-value instead of dividing a change in yy by a change in xx. The slope of the line is 22.

To check slope work, find the true slope yourself from the exact coordinates, then read the given work from the start. When the two xx-values are different, every expression in correct work equals the slope, so the first expression with a different value shows where the error is. Watch for an upside-down fraction, mixed point order, a lost negative sign, a single yy-value divided by a single xx-value, and a misread zero. Test your corrected slope with y1+m(x2βˆ’x1)=y2y_1 + m(x_2 - x_1) = y_2. When the two xx-values are equal, the line is vertical and its slope is undefined.