Chapter 1 · Rational number foundations

Equivalent Fractions and Reciprocals

Learn why fractions that look different can be equal, how to simplify them, and why a nonzero number times its reciprocal is always one.

15 min read

You already add, subtract, multiply and divide fractions. This lesson looks at two ideas underneath that work: fractions that look different but are equal, and pairs of numbers that multiply to 1.

In this lesson, a fraction ab\frac{a}{b} is a number written with two integers (numbers such as −3-3, 00 and 77). The numerator aa is on top and the denominator bb is below, with b≠0b \neq 0. The denominator is never zero because ab\frac{a}{b} means a÷ba \div b, and division by zero is undefined.

Two fractions are equivalent when they are the same number, so they name the same amount of the same whole. Take a strip of paper that is 24 cm long. Cut it into 4 equal pieces and each piece is 6 cm long, so 3 pieces, or 34\frac{3}{4} of the strip, measure 18 cm. Now cut every piece in half. The strip is in 8 equal pieces of 3 cm each, and that same 18 cm is 6 pieces, or 68\frac{6}{8} of the strip. The pieces are half as long and there are twice as many, so the amount has not changed: 34=68\frac{3}{4} = \frac{6}{8}. The comparison works because both fractions describe the same whole, the one strip.

Why does this work for every fraction? Multiplying any number by 1 leaves it unchanged, and nn=1\frac{n}{n} = 1 for every nonzero integer nn. So when you multiply the numerator and the denominator by the same nonzero integer nn, you multiply the fraction by 1 in disguise:

34=34⋅22=3⋅24⋅2=68\frac{3}{4} = \frac{3}{4} \cdot \frac{2}{2} = \frac{3 \cdot 2}{4 \cdot 2} = \frac{6}{8}

The integer nn cannot be zero. That would put a zero in the denominator, and division by zero is undefined. In general:

ab=a⋅nb⋅nfor integers a, b, n with b≠0 and n≠0\frac{a}{b}=\frac{a\cdot n}{b\cdot n}\qquad\text{for integers }a,\ b,\ n\text{ with }b\neq 0\text{ and }n\neq 0

Read that rule from right to left and it tells you how to simplify. A common factor of two integers is a positive integer that divides both with no remainder, so it is never zero. When the numerator and the denominator share a common factor nn greater than 1, dividing both by nn takes out a hidden nn=1\frac{n}{n} = 1. The new fraction is equivalent to the old one, just written more simply.

A fraction is in simplest form when the only common factor of its numerator and denominator is 1. Dividing both by the greatest common factor (GCF), the largest common factor, gets you there in one step. You can also divide out common factors greater than 1 one at a time until the only one left is 1. A negative fraction stays negative when you simplify, because taking out a factor of 1 never changes a sign.

Worked example

Simplify, then build an equivalent fraction

Write 1824\frac{18}{24} in simplest form. Then write an equivalent fraction with a denominator of 20.

  1. List the factors to find the greatest common factor. The factors of 18 are 1, 2, 3, 6, 9 and 18. The factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24. The largest number on both lists is 6.

    GCF of 18 and 24 is 6\text{GCF of }18\text{ and }24\text{ is }6
  2. Write each number as a product with 6. The shared 6s form 6/6, which equals 1, and taking out a factor of 1 does not change the value. This is allowed because 6 is not zero.

    1824=3⋅64⋅6=34⋅66=34⋅1=34\frac{18}{24}=\frac{3\cdot 6}{4\cdot 6}=\frac{3}{4}\cdot\frac{6}{6}=\frac{3}{4}\cdot 1=\frac{3}{4}
  3. Check for simplest form. The factors of 3 are 1 and 3, and the factors of 4 are 1, 2 and 4. The only common factor is 1, so the fraction cannot be simplified any further.

  4. Now go the other way, starting from the simplest form. The denominator must change from 4 to 20, and 4 times 5 is 20. Multiply the numerator and the denominator by 5. Because 5 is not zero, this multiplies by 5/5, which equals 1, so the value stays the same.

    34=34⋅55=3⋅54⋅5=1520\frac{3}{4}=\frac{3}{4}\cdot\frac{5}{5}=\frac{3\cdot 5}{4\cdot 5}=\frac{15}{20}

Answer

In simplest form, 1824=34\frac{18}{24} = \frac{3}{4}. The equivalent fraction with a denominator of 20 is 1520\frac{15}{20}.

Now put 1 to work a second way. What do you multiply 4 by to get exactly 1? Four copies of 14\frac{1}{4} make one whole, so 4⋅14=14 \cdot \frac{1}{4} = 1. What about 23\frac{2}{3}? Multiplying by 3 gives 23⋅3=2\frac{2}{3} \cdot 3 = 2, and then multiplying by 12\frac{1}{2} gives 1. Together, those two steps multiply by 3⋅12=323 \cdot \frac{1}{2} = \frac{3}{2}, so 23⋅32=1\frac{2}{3} \cdot \frac{3}{2} = 1.

The reciprocal of a nonzero number is the number you multiply it by to get a product of exactly 1. Its other name is the multiplicative inverse, because multiplying by it undoes a multiplication: 12⋅34=912 \cdot \frac{3}{4} = 9, and 9⋅43=129 \cdot \frac{4}{3} = 12 again. Multiplying by a nonzero number and then by its reciprocal is the same as multiplying by 1.

For a fraction ab\frac{a}{b} with a≠0a \neq 0 and b≠0b \neq 0, the reciprocal is ba\frac{b}{a}: the numerator and the denominator trade places. The swap works because the product has the same nonzero number on top and bottom, and a nonzero number divided by itself is 1:

ab⋅ba=a⋅bb⋅a=1\frac{a}{b} \cdot \frac{b}{a} = \frac{a \cdot b}{b \cdot a} = 1

Both conditions matter. You need b≠0b \neq 0 for ab\frac{a}{b} to be a number at all, and a≠0a \neq 0 so that ba\frac{b}{a} does not have a zero denominator. That is why zero has no reciprocal: 00 times any number is 00, never 11, and swapping 01\frac{0}{1} would give 10\frac{1}{0}, which is undefined.

Nonzero integers and mixed numbers (a whole number plus a fraction, such as 1121\frac{1}{2}) can be written as fractions, so the same swap finds their reciprocals. You have relied on this idea already: dividing by a nonzero number gives the same result as multiplying by its reciprocal.

Key concept

Two jobs for the number 1

Multiplying by 1 never changes a value, and both ideas in this lesson rest on that.

  • Equivalent fractions: multiplying or dividing the numerator and the denominator by the same nonzero integer nn only puts in or takes out a factor of nn=1\frac{n}{n} = 1, so the fraction keeps its value.
  • Reciprocals: a nonzero number and its reciprocal are the pair whose product is exactly 1. For ab\frac{a}{b} with a≠0a \neq 0 and b≠0b \neq 0, the reciprocal is ba\frac{b}{a}.

Zero is left out each time, because division by zero is undefined.

nn=1  (n≠0)ab⋅ba=1  (a≠0, b≠0)\frac{n}{n}=1\ \ (n\neq 0)\qquad\qquad\frac{a}{b}\cdot\frac{b}{a}=1\ \ (a\neq 0,\ b\neq 0)
A nonzero number times its reciprocal is always 1
NumberWritten as a fractionReciprocalCheck: multiply the pair
55
51\frac{5}{1}
15\frac{1}{5}
5⋅15=55=15 \cdot \frac{1}{5} = \frac{5}{5} = 1
18\frac{1}{8}
18\frac{1}{8}
81=8\frac{8}{1} = 8
18⋅8=88=1\frac{1}{8} \cdot 8 = \frac{8}{8} = 1
34\frac{3}{4}
34\frac{3}{4}
43\frac{4}{3}
34⋅43=1212=1\frac{3}{4} \cdot \frac{4}{3} = \frac{12}{12} = 1
−25-\frac{2}{5}
−25\frac{-2}{5}
5−2=−52\frac{5}{-2} = -\frac{5}{2}
(−25)⋅(−52)=1010=1\left(-\frac{2}{5}\right) \cdot \left(-\frac{5}{2}\right) = \frac{10}{10} = 1
11
11\frac{1}{1}
11=1\frac{1}{1} = 1
1⋅1=11 \cdot 1 = 1
00
01\frac{0}{1}
none
00 times any number is 00, never 11

Worked example

Reciprocal of a mixed number

Find the reciprocal of 2132\frac{1}{3}, and check your answer.

  1. Write the mixed number as one fraction first, because the swap rule needs a single numerator over a single denominator. Two wholes are 6 thirds, and 1 more third makes 7 thirds.

    213=63+13=732\frac{1}{3}=\frac{6}{3}+\frac{1}{3}=\frac{7}{3}
  2. Swap the numerator and the denominator. The swap is allowed because neither 7 nor 3 is zero.

    reciprocal of 73 is 37\text{reciprocal of }\frac{7}{3}\text{ is }\frac{3}{7}
  3. Check with the definition: the number times its reciprocal must equal 1. The product has the same nonzero number, 21, on top and bottom, so it is 1.

    73⋅37=7⋅33⋅7=2121=1\frac{7}{3}\cdot\frac{3}{7}=\frac{7\cdot 3}{3\cdot 7}=\frac{21}{21}=1

Answer

The reciprocal of 2132\frac{1}{3} is 37\frac{3}{7}, because 213⋅37=12\frac{1}{3} \cdot \frac{3}{7} = 1.

Worked example

Simplify, then find the reciprocal

Write −4256-\frac{42}{56} in simplest form. Then find its reciprocal and check it.

  1. Both 42 and 56 are even, so 2 is a common factor, and 2 is not zero. Divide it out. The sign stays negative because you are only taking out 2/2, which equals 1.

    −4256=−21⋅228⋅2=−2128-\frac{42}{56}=-\frac{21\cdot 2}{28\cdot 2}=-\frac{21}{28}
  2. Both 21 and 28 are multiples of 7, so divide out the nonzero common factor 7 as well. Now 3 and 4 have no common factor except 1, so this is simplest form. In all, you divided by 2 times 7, which is 14, the GCF of 42 and 56.

    −2128=−3⋅74⋅7=−34-\frac{21}{28}=-\frac{3\cdot 7}{4\cdot 7}=-\frac{3}{4}
  3. Swap the numerator and the denominator and keep the sign. Neither 3 nor 4 is zero, so the reciprocal exists.

    reciprocal of −34 is −43\text{reciprocal of }-\frac{3}{4}\text{ is }-\frac{4}{3}
  4. Check the product. A negative times a negative is positive, and the top and bottom are the same nonzero number, 12.

    (−34)⋅(−43)=3⋅44⋅3=1212=1\left(-\frac{3}{4}\right)\cdot\left(-\frac{4}{3}\right)=\frac{3\cdot 4}{4\cdot 3}=\frac{12}{12}=1
  5. Compare with swapping the original fraction. Dividing out 14 gives the same result, because equivalent fractions are the same number and a nonzero number has only one reciprocal.

    −5642=−4⋅143⋅14=−43-\frac{56}{42}=-\frac{4\cdot 14}{3\cdot 14}=-\frac{4}{3}

Answer

In simplest form, −4256=−34-\frac{42}{56} = -\frac{3}{4}, and its reciprocal is −43-\frac{4}{3}.

Keep this one idea: the number 1 does both jobs. Multiplying or dividing a numerator and a denominator by the same nonzero integer only puts in or takes out a form of 1, so the new fraction is equivalent to the old one, and dividing out the greatest common factor gives simplest form. A nonzero number and its reciprocal multiply to exactly 1 and have the same sign, while zero has no reciprocal. Next, you will convert between decimals, fractions, mixed numbers and percents.