Chapter 4 Ā· Rational and irrational numbers

Square Roots and the Equations They Solve

Learn what the square root symbol means, why positive numbers have two square roots, and how to solve equations with a squared variable.

16 min read

You already know how to square a number: you multiply it by itself. For example, 72=7ā‹…7=497^2 = 7 \cdot 7 = 49. The name comes from geometry: a square with sides 77 units long has an area of 7ā‹…7=497 \cdot 7 = 49 square units.

A perfect square is the result of squaring a whole number. The whole numbers are 0,1,2,30, 1, 2, 3 and so on, so the perfect squares begin 0,1,4,9,16,250, 1, 4, 9, 16, 25.

In this lesson you work backward. You start with a perfect square, such as 4949, and ask: which number has this square? A number whose square is 4949 is called a square root of 4949.

You will learn what the symbol 49\sqrt{49} means, why a positive number has two square roots, and how square roots help you solve equations such as x2=49x^2 = 49.

The symbol in 49\sqrt{49} is called the radical sign. You read 49\sqrt{49} as the square root of 49.

Here is what it means. For any number n≄0n \ge 0, n\sqrt{n} is the nonnegative number whose square is nn. Nonnegative means zero or positive.

So, for n≄0n \ge 0, a number rr equals n\sqrt{n} exactly when it passes two checks: r≄0r \ge 0 and r2=nr^2 = n.

  • 49=7\sqrt{49} = 7, because 7≄07 \ge 0 and 72=497^2 = 49.
  • 0=0\sqrt{0} = 0, because 0≄00 \ge 0 and 02=00^2 = 0.

When nn is a perfect square, n\sqrt{n} is a whole number. Every number under a radical sign in this lesson is a perfect square, so each root you find is an exact value, not an estimate.

The table shows the perfect squares from 11 to 144144. Each row gives a whole number, its square, and the square root fact that goes with it.

Perfect squares from 1 to 144
Whole numberIts squareSquare root fact
11
11
1=1\sqrt{1} = 1
22
44
4=2\sqrt{4} = 2
33
99
9=3\sqrt{9} = 3
44
1616
16=4\sqrt{16} = 4
55
2525
25=5\sqrt{25} = 5
66
3636
36=6\sqrt{36} = 6
77
4949
49=7\sqrt{49} = 7
88
6464
64=8\sqrt{64} = 8
99
8181
81=9\sqrt{81} = 9
1010
100100
100=10\sqrt{100} = 10
1111
121121
121=11\sqrt{121} = 11
1212
144144
144=12\sqrt{144} = 12

Worked example

Find the square root of a perfect square

Find 81\sqrt{81}.

  1. Say what the symbol asks for. Because 81 is not negative, the symbol has a meaning: it is the nonnegative number whose square is 81. Call that number r.

    r≄0andr2=81r \ge 0 \quad \text{and} \quad r^2 = 81
  2. Look for a whole number whose square is 81. In the table, the row for 9 shows the square 81. Multiply to confirm it.

    92=9ā‹…9=819^2 = 9 \cdot 9 = 81
  3. Check the sign. The number 9 is positive, so it is nonnegative. It passes both checks, so it is the value of the symbol.

    81=9\sqrt{81} = 9

Answer

The square root of 8181 is 99, because 99 is nonnegative and 92=819^2 = 81.

Why does the meaning of n\sqrt{n} insist on a nonnegative number? Because 77 is not the only number whose square is 4949. A negative number times a negative number is positive, so (āˆ’7)2=(āˆ’7)(āˆ’7)=49(-7)^2 = (-7)(-7) = 49.

So 77 and āˆ’7-7 are both square roots of 4949. They are opposites: two numbers the same distance from zero, on opposite sides of it.

Three symbols keep these roots apart:

  • 49=7\sqrt{49} = 7 is the principal square root, the nonnegative one. For n≄0n \ge 0, the value of n\sqrt{n} is never negative.
  • āˆ’49=āˆ’7-\sqrt{49} = -7 is the negative square root. The minus sign sits outside the radical sign, so the number under it is still 4949.
  • ±49\pm\sqrt{49} is read plus or minus the square root of 49. It names both roots at once: 77 and āˆ’7-7.

Does every number have two square roots? No. It depends on whether the number is positive, zero or negative. Here, number means a real number: any number on the number line.

  • A positive number has exactly two real square roots, and they are opposites. Among nonnegative numbers, a larger number has a larger square: 62=366^2 = 36, 72=497^2 = 49, 82=648^2 = 64. So only one nonnegative number, 77, has the square 4949. A number and its opposite have equal squares, so on the negative side only āˆ’7-7 works.
  • Zero has exactly one square root, which is 00. You know that 02=00^2 = 0, and every other real number has a positive square.
  • A negative number has no real square root. A positive number times itself is positive, a negative number times itself is positive, and 0ā‹…0=00 \cdot 0 = 0. So the square of a real number is never negative. That is why the meaning of n\sqrt{n} requires n≄0n \ge 0.

Worked example

Name both square roots

Find the two square roots of 100100. Then give the values of 100\sqrt{100}, āˆ’100-\sqrt{100} and ±100\pm\sqrt{100}.

  1. Find the nonnegative number whose square is 100. Ten times ten is 100, and 10 is nonnegative, so 10 is the principal square root.

    102=10ā‹…10=100,100=1010^2 = 10 \cdot 10 = 100, \quad \sqrt{100} = 10
  2. Take the opposite of 10. A negative number times a negative number is positive, so negative 10 also has the square 100. It is the negative square root, written with a minus sign outside the radical sign.

    (āˆ’10)2=(āˆ’10)(āˆ’10)=100,āˆ’100=āˆ’10(-10)^2 = (-10)(-10) = 100, \quad -\sqrt{100} = -10
  3. Count the roots. Because 100 is positive, it has exactly two real square roots, so 10 and negative 10 are all of them. The plus-or-minus symbol names both at once.

    ±100=±10\pm\sqrt{100} = \pm 10

Answer

The square roots of 100100 are 1010 and āˆ’10-10. So 100=10\sqrt{100} = 10, āˆ’100=āˆ’10-\sqrt{100} = -10, and ±100\pm\sqrt{100} names both 1010 and āˆ’10-10.

Now you can use square roots to solve equations. An equation says that two expressions are equal. A solution of an equation is a value of the variable that makes it true.

Take x2=49x^2 = 49, where the variable xx stands for a real number. The equation asks: which real numbers have the square 49? That is the same question as what are the square roots of 49? You already know them: 77 and āˆ’7-7. So the equation has two solutions, x=7x = 7 and x=āˆ’7x = -7. You can write them together as x=±7x = \pm 7.

The same reasoning works for any equation of the form x2=nx^2 = n: its real solutions are exactly the real square roots of nn. So before you solve, compare nn with zero to see how many solutions to expect.

Key concept

The symbol names one root; the equation asks for all

For n≄0n \ge 0, the symbol n\sqrt{n} names exactly one number: the principal square root, the nonnegative number whose square is nn.

The equation x2=nx^2 = n asks for every real number xx whose square is nn:

  • If n>0n > 0, there are two solutions, x=nx = \sqrt{n} and x=āˆ’nx = -\sqrt{n}, written x=±nx = \pm\sqrt{n}.
  • If n=0n = 0, there is one solution, x=0x = 0.
  • If n<0n < 0, there is no real solution, because the square of a real number is never negative.
IfĀ n>0,x2=nĀ exactlyĀ whenĀ x=nĀ orĀ x=āˆ’n\text{If } n > 0, \quad x^2 = n \text{ exactly when } x = \sqrt{n} \text{ or } x = -\sqrt{n}
The three cases, each with an example
EquationRight sideReal solutionsReason
x2=36x^2 = 36
positive: 36>036 > 0
two: x=6x = 6 and x=āˆ’6x = -6
62=366^2 = 36 and (āˆ’6)2=36(-6)^2 = 36
x2=0x^2 = 0
zero
one: x=0x = 0
02=00^2 = 0, and every other real number has a positive square
x2=āˆ’36x^2 = -36
negative: āˆ’36<0-36 < 0
none
the square of a real number is never negative

Worked example

Solve an equation with two solutions

Solve x2=121x^2 = 121, where xx is a real number.

  1. Compare the right side with zero. Since 121 is positive, the equation has exactly two real solutions: the principal square root of 121 and its opposite.

    x=121orx=āˆ’121x = \sqrt{121} \quad \text{or} \quad x = -\sqrt{121}
  2. Find the principal square root. Eleven times eleven is 121, and 11 is nonnegative.

    11ā‹…11=110+11=121,121=1111 \cdot 11 = 110 + 11 = 121, \quad \sqrt{121} = 11
  3. Write both solutions. The negative solution is the opposite of 11.

    x=11orx=āˆ’11x = 11 \quad \text{or} \quad x = -11
  4. Check each value in the original equation. Both squares equal 121, so both values are solutions.

    112=121and(āˆ’11)2=(āˆ’11)(āˆ’11)=12111^2 = 121 \quad \text{and} \quad (-11)^2 = (-11)(-11) = 121

Answer

The solutions of x2=121x^2 = 121 are x=11x = 11 and x=āˆ’11x = -11, which you can write as x=±11x = \pm 11.

Worked example

Find the side of a square from its area

A square garden has an area of 144144 square feet. How long is each side?

  1. Define the variable and the values it can take. Let s be the length of one side, measured in feet. A side length is positive, so s must be greater than zero.

    s>0s > 0
  2. Write an equation. The area of a square is its side length times itself, and here the area is 144 square feet.

    s2=144s^2 = 144
  3. Solve the equation. Since 144 is positive, there are two real solutions: the principal square root of 144 and its opposite. Twelve times twelve is 144, so they are 12 and negative 12.

    12ā‹…12=120+24=144,s=±144=±1212 \cdot 12 = 120 + 24 = 144, \quad s = \pm\sqrt{144} = \pm 12
  4. Use the condition on s. Negative 12 solves the equation, but it is not greater than zero, so it cannot be a length. Keep only 12.

    s=12s = 12
  5. Check against the problem. A side of 12 feet gives an area of 12 feet times 12 feet, which is 144 square feet.

    12Ā ftā‹…12Ā ft=144Ā squareĀ feet12 \text{ ft} \cdot 12 \text{ ft} = 144 \text{ square feet}

Answer

Each side of the garden is 1212 feet long.

Takeaway. For n≄0n \ge 0, the symbol n\sqrt{n} names one number: the nonnegative principal square root, so 49=7\sqrt{49} = 7. The equation x2=nx^2 = n asks for every real number whose square is nn. It has two solutions, x=±nx = \pm\sqrt{n}, when n>0n > 0; one solution, x=0x = 0, when n=0n = 0; and no real solution when n<0n < 0. When a situation limits the variable, as a length does, keep only the solutions that fit.

Next, you will work backward from cubes such as 23=82^3 = 8: you will find cube roots and use them to solve equations.