Chapter 11 ยท Transformations, congruence, and similarity

Rotate Figures and Write Transformation Rules

Turn points and polygons about the origin by quarter, half and three-quarter turns, then write coordinate rules that tell where a transformation sends every point.

17 min read

A transformation is a rule that tells where each point of a figure goes. The figure you get is called the image. You have already reflected figures across a line. Now you will turn them.

A rotation turns a figure around one fixed point, called the center of rotation. The center stays where it is. Every other point travels around the center through the same angle, called the angle of rotation, and in the same direction: clockwise (the way clock hands move) or counterclockwise (the opposite way).

A rotation does not stretch or bend anything. It turns the figure as one rigid piece, so:

  • each point and its image are the same distance from the center, and
  • every segment keeps its length while its direction turns through the angle of rotation.

Distances and lengths here are counted in grid units and are never negative.

In this lesson the center is always the origin, (0,0)(0, 0). The angle is 90โˆ˜90^\circ (a quarter turn), 180โˆ˜180^\circ (a half turn) or 270โˆ˜270^\circ (a three-quarter turn). You will work from exact coordinates, not from how a drawing looks.

Start with one point and one turn: rotate (3,1)(3, 1) by 90โˆ˜90^\circ counterclockwise about the origin.

Think of the path from the origin to (3,1)(3, 1) as two straight steps: 33 units right, along the horizontal xx-axis, then 11 unit up, parallel to the vertical yy-axis. The rotation turns the whole path as one rigid piece, so each step keeps its length and turns 90โˆ˜90^\circ counterclockwise.

  • A step right becomes a step up. The half of the yy-axis that points up is exactly 90โˆ˜90^\circ counterclockwise from the half of the xx-axis that points right.
  • A step up becomes a step left. The half of the xx-axis that points left is exactly 90โˆ˜90^\circ counterclockwise from the half of the yy-axis that points up.

So the turned path is 33 units up, then 11 unit left, and it ends at (โˆ’1,3)(-1, 3).

The figure shows both paths with verified coordinates. The steps to Point G at (3,1)(3, 1) are two sides of the triangle with corners (0,0)(0, 0), (3,0)(3, 0) and (3,1)(3, 1). The turned steps to Point H at (โˆ’1,3)(-1, 3) are two sides of the triangle with corners (0,0)(0, 0), (0,3)(0, 3) and (โˆ’1,3)(-1, 3).

Coordinate grid from x -4 to 4 and y -2 to 4, with a grid step of 1, showing 5 plotted elements. Details: polygon with 3 vertices; polygon with 3 vertices; point at (0, 0), named (0, 0); point at (3, 1), named Point G; point at (-1, 3), named Point H.
Point G at (3,1)(3, 1) turns 90โˆ˜90^\circ counterclockwise about the origin, (0,0)(0, 0), to Point H at (โˆ’1,3)(-1, 3).

The same reasoning works for any point. Let xx and yy stand for its coordinates in grid units. Each can be any number: positive, negative or zero. The path from the origin to (x,y)(x, y) is xx units right, then yy units up. After a 90โˆ˜90^\circ counterclockwise turn about the origin, the path is xx units up, then yy units left. So the image has xx-coordinate โˆ’y-y and yy-coordinate xx.

You can write this in one line, called a rule: (x,y)โ†’(โˆ’y,x)(x, y) \to (-y, x). Read the arrow as goes to. The symbol โˆ’y-y means the opposite of yy, the same number with its sign changed. This rule belongs to one turn only: 90โˆ˜90^\circ counterclockwise about the origin.

The rule holds whatever the signs of xx and yy. When xx is negative, the first step goes left, and the turn carries a step left to a step down, so the image's yy-coordinate is still xx. When yy is negative, the second step goes down, and the turn carries a step down to a step right, so the image's xx-coordinate is still โˆ’y-y.

Rotations about the origin: where each step goes and the rule for any point (x, y)
Turn about the originA step right becomesA step up becomesRule for any point (x, y)Image of (3, 1)
90โˆ˜90^\circ counterclockwise, or 270โˆ˜270^\circ clockwise
a step up
a step left
(x,y)โ†’(โˆ’y,x)(x, y) \to (-y, x)
(โˆ’1,3)(-1, 3)
180โˆ˜180^\circ in either direction
a step left
a step down
(x,y)โ†’(โˆ’x,โˆ’y)(x, y) \to (-x, -y)
(โˆ’3,โˆ’1)(-3, -1)
270โˆ˜270^\circ counterclockwise, or 90โˆ˜90^\circ clockwise
a step down
a step right
(x,y)โ†’(y,โˆ’x)(x, y) \to (y, -x)
(1,โˆ’3)(1, -3)

Worked example

Rotate a triangle a quarter turn

A triangle has vertices Point A at (2,1)(2, 1), Point B at (5,1)(5, 1) and Point C at (5,3)(5, 3). Rotate the triangle 90โˆ˜90^\circ counterclockwise about the origin. What are the vertices of its image?

  1. State the conditions and pick the rule. The center is the origin and the turn is exactly 90ยฐ counterclockwise, so every point (x, y) goes to (-y, x).

    (x,y)โ†’(โˆ’y,x)(x, y) \to (-y, x)
  2. Apply the rule to Point A, where x = 2 and y = 1. The image's x-coordinate is the opposite of y, which is -1. Its y-coordinate is x, which is 2.

    (2,1)โ†’(โˆ’1,2)(2, 1) \to (-1, 2)
  3. Apply the rule to Point B, where x = 5 and y = 1. The opposite of y is -1, and x is 5.

    (5,1)โ†’(โˆ’1,5)(5, 1) \to (-1, 5)
  4. Apply the rule to Point C, where x = 5 and y = 3. The opposite of y is -3, and x is 5.

    (5,3)โ†’(โˆ’3,5)(5, 3) \to (-3, 5)
  5. Join the three image points in the same order as the original vertices. This gives the image triangle, because a rotation turns each side as one rigid piece. In the figure after this example, the x-axis is horizontal and the y-axis is vertical. Points A, B and C are the original vertices, and Points D, E and F are their images in that order.

  6. Check one side with exact coordinates, not by eye. Side AB joins (2, 1) and (5, 1). Both have y = 1, so the side is horizontal and 5 - 2 = 3 grid units long. Its image, side DE, joins (-1, 2) and (-1, 5). Both have x = -1, so it is vertical and 5 - 2 = 3 grid units long. A horizontal side became a vertical side of the same length, which fits a quarter turn.

    AB=5โˆ’2=3DE=5โˆ’2=3AB = 5 - 2 = 3 \qquad DE = 5 - 2 = 3

Answer

The image triangle has vertices (โˆ’1,2)(-1, 2), (โˆ’1,5)(-1, 5) and (โˆ’3,5)(-3, 5). These are Points D, E and F in the figure.

Coordinate grid from x -6 to 6 and y -2 to 6, with a grid step of 1, showing 9 plotted elements. Details: polygon with 3 vertices; polygon with 3 vertices; point at (0, 0), named (0, 0); point at (2, 1), named Point A; point at (5, 1), named Point B; point at (5, 3), named Point C; point at (-1, 2), named Point D; point at (-1, 5), named Point E; point at (-3, 5), named Point F.
Triangle ABC with vertices (2,1)(2, 1), (5,1)(5, 1), (5,3)(5, 3) and its image DEF with vertices (โˆ’1,2)(-1, 2), (โˆ’1,5)(-1, 5), (โˆ’3,5)(-3, 5) after a 90โˆ˜90^\circ counterclockwise turn about the origin.

Worked example

Rotate clockwise with negative coordinates

Triangle PQRPQR has vertices P(โˆ’4,1)P(-4, 1), Q(โˆ’1,3)Q(-1, 3) and R(โˆ’2,โˆ’2)R(-2, -2). Rotate it 90โˆ˜90^\circ clockwise about the origin. What are the vertices of the image?

  1. Pick the rule from its conditions. The center is the origin. A 90ยฐ clockwise turn puts every point in the same place as a 270ยฐ counterclockwise turn, because a full turn is 360ยฐ and 360ยฐ - 90ยฐ = 270ยฐ. So every point (x, y) goes to (y, -x).

    (x,y)โ†’(y,โˆ’x)(x, y) \to (y, -x)
  2. Substitute P, where x = -4 and y = 1. Keep the parentheses around the negative coordinate: the opposite of -4 is 4.

    P(โˆ’4,1)โ†’(1,โˆ’(โˆ’4))=(1,4)P(-4, 1) \to (1, -(-4)) = (1, 4)
  3. Substitute Q, where x = -1 and y = 3. The opposite of -1 is 1.

    Q(โˆ’1,3)โ†’(3,โˆ’(โˆ’1))=(3,1)Q(-1, 3) \to (3, -(-1)) = (3, 1)
  4. Substitute R, where x = -2 and y = -2. The first coordinate of the image is y itself, so it stays -2. Only x changes to its opposite, which is 2.

    R(โˆ’2,โˆ’2)โ†’(โˆ’2,โˆ’(โˆ’2))=(โˆ’2,2)R(-2, -2) \to (-2, -(-2)) = (-2, 2)

Answer

The image of triangle PQRPQR has vertices (1,4)(1, 4), (3,1)(3, 1) and (โˆ’2,2)(-2, 2), which are the images of PP, QQ and RR in that order.

So far you have used rules. Now you will write the rule for a transformation: one line with an arrow that tells where every point (x,y)(x, y) goes.

If you know what the transformation does, put it into coordinates.

  • Reflecting across the xx-axis keeps xx and changes yy to its opposite: (x,y)โ†’(x,โˆ’y)(x, y) \to (x, -y).
  • Reflecting across the yy-axis changes xx to its opposite and keeps yy: (x,y)โ†’(โˆ’x,y)(x, y) \to (-x, y).
  • A translation slides every point the same distance in the same direction. Sliding 33 units right and 22 units down adds 33 to xx and subtracts 22 from yy: (x,y)โ†’(x+3,yโˆ’2)(x, y) \to (x + 3, y - 2).
  • A 180โˆ˜180^\circ rotation about the origin changes both xx and yy to their opposites: (x,y)โ†’(โˆ’x,โˆ’y)(x, y) \to (-x, -y).

Sometimes you get coordinates instead of a description: each vertex of a figure matched with the vertex of the image it lands on. These matched pairs are called corresponding vertices. Then you compare the pairs, write the pattern you find using xx and yy, and test it on every pair with exact coordinates.

Key concept

A rule tells where every point goes

A rule such as (x,y)โ†’(โˆ’y,x)(x, y) \to (-y, x) describes a whole transformation in one line. The left side stands for any point of the figure, and the right side gives the coordinates of its image.

  • To use a rule, substitute a point's exact coordinates. Read โˆ’x-x and โˆ’y-y as opposites: the opposite of a negative number is positive.
  • To write a rule, find the one pattern that fits every point and its image. A pattern that fits only some pairs is not the rule.

Each rule holds only under its conditions. The rotation rules in this lesson are for turns about the origin by exactly the stated angle and direction.

Worked example

Write the rule from corresponding vertices

A transformation sends each vertex of a triangle to its image: (2,2)โ†’(โˆ’2,2)(2, 2) \to (-2, 2), (5,1)โ†’(โˆ’1,5)(5, 1) \to (-1, 5) and (3,4)โ†’(โˆ’4,3)(3, 4) \to (-4, 3). Write the rule for this transformation.

  1. Start with the first pair, where (2, 2) goes to (-2, 2). The numbers suggest that x changed to its opposite and y stayed the same. That is the rule for a reflection across the y-axis, which sends (x, y) to (-x, y). Treat it as a guess to test, because one pair can fit more than one rule.

    (2,2)โ†’(โˆ’2,2)(2, 2) \to (-2, 2)
  2. Test the guess on the second pair, using exact coordinates. With x = 5 and y = 1, the guess gives (-5, 1). The given image is (-1, 5). These are different points, so the guess is not the rule.

    (5,1)โ†’(โˆ’5,1)โ‰ (โˆ’1,5)(5, 1) \to (-5, 1) \ne (-1, 5)
  3. Study the second pair, where (5, 1) goes to (-1, 5) and the two coordinates are different numbers. The 5 moved from first place to second place. The 1 moved from second place to first place and changed to its opposite. So the first coordinate of the image is -y and the second coordinate is x.

    (x,y)โ†’(โˆ’y,x)(x, y) \to (-y, x)
  4. Test this rule on every pair. From (2, 2) it gives (-2, 2). From (5, 1) it gives (-1, 5). From (3, 4) it gives (-4, 3). All three match the given images.

    (2,2)โ†’(โˆ’2,2)(5,1)โ†’(โˆ’1,5)(3,4)โ†’(โˆ’4,3)(2, 2) \to (-2, 2) \qquad (5, 1) \to (-1, 5) \qquad (3, 4) \to (-4, 3)

Answer

The rule for this transformation is (x,y)โ†’(โˆ’y,x)(x, y) \to (-y, x). It fits all three pairs of corresponding vertices, and it is the rule for a 90โˆ˜90^\circ counterclockwise rotation about the origin.

Takeaway. A rotation turns a figure about a fixed center without changing its size or shape. When the center is the origin and the turn is 90โˆ˜90^\circ, 180โˆ˜180^\circ or 270โˆ˜270^\circ, the turn changes the coordinates of every point in one fixed way, so you can rotate a figure exactly by applying the rule for that turn to each vertex. A rule such as (x,y)โ†’(โˆ’y,x)(x, y) \to (-y, x) speaks for every point at once. When you write a rule yourself, make sure it fits every pair of corresponding vertices, using exact coordinates and not the look of a drawing.

Next, you will describe a transformation from a figure and its image, verify that these transformations keep lengths and angle measures the same and keep parallel lines parallel, and find and correct errors in graphed transformations.