Chapter 2 ยท Proportional reasoning foundations

Solve, Interpret, and Check Proportions

Solve proportions with cross products, set them up for constant-rate word problems, and find and correct errors in worked solutions.

20 min read

You already know how to find a unit rate, such as the number of liters a pump moves in 11 minute. Now you will use equal ratios to find a number you do not know yet.

A ratio compares two quantities by division, and you can write it as a fraction. A proportion is an equation that says two ratios are equal. Every denominator in a proportion must be nonzero, because division by zero is undefined. Here is a proportion:

34=1520\frac{3}{4} = \frac{15}{20}

This proportion is true because both ratios have the same value: 3รท4=0.753 \div 4 = 0.75 and 15รท20=0.7515 \div 20 = 0.75. The divisors 44 and 2020 are nonzero, so both quotients exist. You can also see it by scaling: multiplying 33 and 44 by the same nonzero number, 55, gives 1515 and 2020 without changing the value of the ratio.

To solve a proportion means to find the value of the unknown that makes the two ratios equal. Take x20=34\frac{x}{20} = \frac{3}{4}, where xx stands for an unknown number and both denominators are nonzero. The denominator 44 is multiplied by 55 to make 2020, so the numerator 33 must be multiplied by 55 as well: x=15x = 15.

Scaling is quick when the multiplier is easy to spot. When it is not, you need a method that does not depend on spotting it.

Let aa, bb, cc and dd stand for numbers, with bโ‰ 0b \neq 0 and dโ‰ 0d \neq 0, and suppose ab=cd\frac{a}{b} = \frac{c}{d}.

Multiply both sides by bdbd. Because bb and dd are both nonzero, bdbd is nonzero too. Multiplying both sides of an equation by the same nonzero number, positive or negative, gives an equation with exactly the same solutions.

On the left, bb divides out and leaves adad. On the right, dd divides out and leaves bcbc. The products adad and bcbc are called cross products, because each numerator is multiplied by the denominator of the other ratio.

abโ‹…bd=cdโ‹…bdโŸนad=bc\frac{a}{b} \cdot bd = \frac{c}{d} \cdot bd \quad \Longrightarrow \quad ad = bc

Key concept

Equal ratios have equal cross products

When bโ‰ 0b \neq 0 and dโ‰ 0d \neq 0, the proportion ab=cd\frac{a}{b} = \frac{c}{d} is true exactly when the cross products adad and bcbc are equal.

To solve a proportion:

  1. Note which values the unknown may take. An unknown in a denominator cannot be 00, because division by zero is undefined.
  2. Write the cross-product equation.
  3. If the number multiplying the unknown is nonzero, divide both sides by it.
  4. Check your value in the original proportion.
ab=cdโ€…โ€Šย exactlyย whenย โ€…โ€Šad=bc(bโ‰ 0,โ€…โ€Šdโ‰ 0)\frac{a}{b} = \frac{c}{d} \;\text{ exactly when }\; ad = bc \qquad (b \neq 0,\; d \neq 0)

Worked example

Unknown in a numerator

Solve x15=46\frac{x}{15} = \frac{4}{6}, where xx stands for an unknown number.

  1. Check the conditions. The denominators 15 and 6 are both nonzero, so both ratios are defined. The unknown x is a numerator, so it may be any number.

    15โ‰ 0,6โ‰ 015 \neq 0, \quad 6 \neq 0
  2. Write the cross products: multiply each numerator by the other ratio's denominator. This is the same as multiplying both sides by 15 times 6, which is 90 and not zero, so the new equation has the same solution.

    xโ‹…6=15โ‹…4x \cdot 6 = 15 \cdot 4
  3. Multiply on each side: x times 6 is 6x, and 15 times 4 is 60.

    6x=606x = 60
  4. Divide both sides by 6. Dividing both sides by the same nonzero number keeps the equation true for the same x.

    x=606=10x = \frac{60}{6} = 10
  5. Check in the original proportion. Put 10 in place of x and simplify each ratio. Both ratios equal two thirds, so they match.

    1015=23and46=23\frac{10}{15} = \frac{2}{3} \quad \text{and} \quad \frac{4}{6} = \frac{2}{3}

Answer

The solution is x=10x = 10, because 1015\frac{10}{15} and 46\frac{4}{6} both equal 23\frac{2}{3}.

Worked example

Unknown in a denominator

Solve 14x=45\frac{14}{x} = \frac{4}{5}, where xx stands for an unknown nonzero number.

  1. State the condition on the unknown. Here x is a denominator, and division by zero is undefined, so x cannot be 0. The other denominator, 5, is also nonzero.

    xโ‰ 0x \neq 0
  2. Write the cross products. This multiplies both sides by 5x, which is nonzero because 5 and x are both nonzero, so the new equation has the same solution.

    14โ‹…5=xโ‹…414 \cdot 5 = x \cdot 4
  3. Multiply on each side: 14 times 5 is 70, and x times 4 is 4x.

    70=4x70 = 4x
  4. Divide both sides by 4, which is nonzero, to leave x alone.

    x=704=17.5x = \frac{70}{4} = 17.5
  5. Check. The value 17.5 is not zero, so it is allowed as a denominator. Put it in place of x: 14 divided by 17.5 is 0.8, and 4 divided by 5 is 0.8.

    1417.5=0.8and45=0.8\frac{14}{17.5} = 0.8 \quad \text{and} \quad \frac{4}{5} = 0.8

Answer

The solution is x=17.5x = 17.5. This value is exact, and it makes both ratios equal to 0.80.8.

A proportion fits a word problem only when the two quantities are in a proportional relationship: every pair of matching values gives the same ratio, so the unit rate is constant. The quantity you divide by must be nonzero. Look for words such as at a constant rate or at the same rate. If the rate changes, a proportion does not apply.

When it does apply:

  • Define the variable. Say what it counts, its unit, and which values make sense.
  • Write both ratios with the same units in the same positions.
  • Solve, then check the answer against the situation.

The table organizes a problem about a pump that runs at a constant rate. It moves 3636 liters in 88 minutes, and you want the number of minutes, tt, that it needs to move 9999 liters. A pumping time is positive, so t>0t > 0.

Organize the pump problem before writing an equation
QuantityKnown runNew run
Volume (liters)
3636
9999
Time (minutes)
88
tt

Worked example

A constant-rate word problem

A pump fills a tank at a constant rate. It moves 3636 liters in 88 minutes. How many minutes does it need to move 9999 liters?

  1. Define the variable and its domain. Let t be the number of minutes the pump needs to move 99 liters. Pumping takes a positive amount of time, so t is greater than 0. That means t is not zero and may be a denominator.

    t>0t > 0
  2. Read each column of the table as a ratio of liters to minutes. The rate is constant, so the two ratios are equal. Liters are on top in both ratios, and minutes are on the bottom in both.

    36ย liters8ย minutes=99ย literstย minutes\frac{36 \text{ liters}}{8 \text{ minutes}} = \frac{99 \text{ liters}}{t \text{ minutes}}
  3. Write the cross products. The denominators 8 and t are both nonzero, so this step keeps the same solution.

    36โ‹…t=8โ‹…9936 \cdot t = 8 \cdot 99
  4. Multiply on the right: 8 times 99 is 792.

    36t=79236t = 792
  5. Divide both sides by 36, which is nonzero.

    t=79236=22t = \frac{792}{36} = 22
  6. Check with unit rates and with size. The divisors 8 and 22 are nonzero, and both runs give 4.5 liters per minute. Also, 99 liters is between 2 and 3 times 36 liters, and 22 minutes is between 16 and 24 minutes.

    368=4.5and9922=4.5\frac{36}{8} = 4.5 \quad \text{and} \quad \frac{99}{22} = 4.5

Answer

The pump needs 2222 minutes to move 9999 liters.

Checking also helps you judge a finished solution, including your own. Errors can hide in the setup, as in the warning above, or in the solving steps. To find and correct an error:

  • Test the answer. Put it into the original proportion. Use the exact value, because a rounded value is only an approximation and can make equal ratios look slightly different. If the two ratios are not equal, there is an error.
  • Trace the lines. For each line, ask what was done to both sides and whether that step keeps the equation true.
  • Fix the first wrong line, then finish and check again.

Dev solved 8x=1221\frac{8}{x} = \frac{12}{21}, where xx stands for an unknown nonzero number. His work is shown below.

Dev's work
LineDev wrote
1
8โ‹…12=21โ‹…x8 \cdot 12 = 21 \cdot x
2
96=21x96 = 21x
3
x=9621โ‰ˆ4.57x = \frac{96}{21} \approx 4.57

Worked example

Find and correct the error

Dev solved 8x=1221\frac{8}{x} = \frac{12}{21}, where xx stands for an unknown nonzero number. He got x=9621โ‰ˆ4.57x = \frac{96}{21} \approx 4.57. Decide whether his answer is correct. If it is not, find the first wrong line in his work and correct it.

  1. Test the answer with its exact value. First simplify 96/21 to 32/7 by dividing the top and bottom by 3. Then put 32/7 in place of x on the left side. Dividing by the nonzero fraction 32/7 is the same as multiplying by its reciprocal, 7/32.

    9621=327,8รท327=8โ‹…732=5632=74\frac{96}{21} = \frac{32}{7}, \qquad 8 \div \frac{32}{7} = 8 \cdot \frac{7}{32} = \frac{56}{32} = \frac{7}{4}
  2. Compare with the right side. 12/21 simplifies to 4/7 when you divide the top and bottom by 3. The left side, 7/4, is greater than 1, and the right side, 4/7, is less than 1. The ratios are not equal, so the answer is wrong.

    1221=47,74โ‰ 47\frac{12}{21} = \frac{4}{7}, \qquad \frac{7}{4} \neq \frac{4}{7}
  3. Trace the lines. A valid first step multiplies both sides by 21x, which is nonzero. That gives 8 times 21 on the left and 12 times x on the right. Line 1 instead multiplies the two numerators together and the two denominators together, so it does not follow from the proportion. Lines 2 and 3 follow correctly from line 1, so line 1 is the only error.

  4. Correct line 1. Both denominators, x and 21, are nonzero, so write the true cross products: 8 times 21 and x times 12.

    8โ‹…21=xโ‹…128 \cdot 21 = x \cdot 12
  5. Multiply on each side, then divide both sides by 12, which is nonzero.

    168=12x,x=16812=14168 = 12x, \qquad x = \frac{168}{12} = 14
  6. Check the corrected answer. The value 14 is not zero, so it is allowed as a denominator. Put it in place of x: both ratios simplify to 4/7.

    814=47and1221=47\frac{8}{14} = \frac{4}{7} \quad \text{and} \quad \frac{12}{21} = \frac{4}{7}

Answer

Dev's answer is not correct. His error is in line 1, where he multiplied straight across instead of forming cross products. The correct solution is x=14x = 14.

Takeaway. A proportion says that two ratios are equal, and every denominator in it must be nonzero. Under that condition the cross products are equal, so you can rewrite the proportion as a simpler equation and divide both sides by the number multiplying the unknown, as long as that number is not zero. In a word problem, use a proportion only when the rate is constant, define your variable with its unit, and keep matching units in matching positions. Always test an answer in the original proportion with its exact value. That test is also how you find errors in a solution.

Next, you will use proportions to solve word problems about scale drawings.