Chapter 10 ยท Geometry foundations

Angle Relationships: Measures, Equations, and Errors

Turn stated angle relationships into equations, solve them to find missing angle measures, and check answers to find and fix mistakes.

18 min read

In this lesson you use angle relationships to find unknown angle measures, write and solve equations, and find and fix mistakes. Every relationship you need is stated in words. You work only from those stated facts, never from how an angle might look. An angle has two sides that meet at a point called its vertex. All measures are in degrees, and every angle here has a positive measure, greater than 0โˆ˜0^\circ. You write mโˆ 1m\angle 1 for the measure of โˆ 1\angle 1. For example, mโˆ 1=40โˆ˜m\angle 1 = 40^\circ means that โˆ 1\angle 1 measures 4040 degrees.

What each stated relationship lets you write
Stated relationshipWhat it meansWhat you can write
โˆ 1\angle 1 and โˆ 2\angle 2 are complementary
Their measures add to 90โˆ˜90^\circ.
mโˆ 1+mโˆ 2=90โˆ˜m\angle 1 + m\angle 2 = 90^\circ
โˆ 1\angle 1 and โˆ 2\angle 2 are supplementary
Their measures add to 180โˆ˜180^\circ.
mโˆ 1+mโˆ 2=180โˆ˜m\angle 1 + m\angle 2 = 180^\circ
โˆ 1\angle 1 and โˆ 2\angle 2 are vertical angles
They are opposite each other where two lines cross, sharing the vertex but no side. Their measures are equal.
mโˆ 1=mโˆ 2m\angle 1 = m\angle 2, an equation with no number of degrees in it
โˆ 1\angle 1 and โˆ 2\angle 2 are adjacent
They share a vertex and a side and do not overlap.
No equation by itself. If the whole angle they fill has a stated measure, their measures add to that measure.

Being adjacent tells you where two angles sit, not how big they are. Two adjacent angles might add to 50โˆ˜50^\circ, to 150โˆ˜150^\circ, or to many other totals. So being adjacent gives you no equation by itself. You get an equation when the whole angle they fill has a stated measure.

Suppose โˆ ABD\angle ABD and โˆ DBC\angle DBC are adjacent, sharing vertex BB and side BDBD. Together they form โˆ ABC\angle ABC, and mโˆ ABC=130โˆ˜m\angle ABC = 130^\circ. The two parts add to that stated whole. If mโˆ ABD=85โˆ˜m\angle ABD = 85^\circ, you write 85โˆ˜+mโˆ DBC=130โˆ˜85^\circ + m\angle DBC = 130^\circ. Subtracting 85โˆ˜85^\circ from both sides keeps the equation true and gives mโˆ DBC=130โˆ˜โˆ’85โˆ˜=45โˆ˜m\angle DBC = 130^\circ - 85^\circ = 45^\circ. Check: both measures are positive, and 85โˆ˜+45โˆ˜=130โˆ˜85^\circ + 45^\circ = 130^\circ.

Complementary and supplementary are the opposite kind of fact. They describe size only, so two such angles may be adjacent or apart.

Key concept

Write only what a stated fact gives, then check

Write only the equation that a stated fact gives you.

  • Complementary: the two measures add to 90โˆ˜90^\circ.
  • Supplementary: the two measures add to 180โˆ˜180^\circ.
  • Vertical: the two measures are equal. This is an equation with no number of degrees in it.
  • Adjacent: no equation by itself. When the whole angle they fill has a stated measure, the two measures add to that measure.

Then solve. Check that every angle measure is positive and fits every stated fact.

Worked example

Find measures from stated facts

You are told that mโˆ 1=34โˆ˜m\angle 1 = 34^\circ, that โˆ 1\angle 1 and โˆ 2\angle 2 are complementary, that โˆ 1\angle 1 and โˆ 3\angle 3 are supplementary, and that โˆ 3\angle 3 and โˆ 4\angle 4 are vertical angles. Find mโˆ 2m\angle 2, mโˆ 3m\angle 3, and mโˆ 4m\angle 4.

  1. Start with the complementary pair. Complementary angles have measures that add to 90โˆ˜90^\circ. Write that sum and put in the measure you know.

    34โˆ˜+mโˆ 2=90โˆ˜34^\circ + m\angle 2 = 90^\circ
  2. Subtract 34โˆ˜34^\circ from both sides. Doing the same thing to both sides keeps the equation true.

    mโˆ 2=90โˆ˜โˆ’34โˆ˜=56โˆ˜m\angle 2 = 90^\circ - 34^\circ = 56^\circ
  3. Supplementary angles have measures that add to 180โˆ˜180^\circ. Write that sum, then subtract 34โˆ˜34^\circ from both sides, as before.

    34โˆ˜+mโˆ 3=180โˆ˜โ‡’mโˆ 3=180โˆ˜โˆ’34โˆ˜=146โˆ˜34^\circ + m\angle 3 = 180^\circ \quad\Rightarrow\quad m\angle 3 = 180^\circ - 34^\circ = 146^\circ
  4. Vertical angles have equal measures. That equation has no number of degrees in it, so you use the measure you just found for โˆ 3\angle 3.

    mโˆ 4=mโˆ 3=146โˆ˜m\angle 4 = m\angle 3 = 146^\circ
  5. Check every stated fact. All the measures are positive. The complementary pair adds to 90โˆ˜90^\circ, the supplementary pair adds to 180โˆ˜180^\circ, and the vertical pair is equal.

    34โˆ˜+56โˆ˜=90โˆ˜,34โˆ˜+146โˆ˜=180โˆ˜,146โˆ˜=146โˆ˜34^\circ + 56^\circ = 90^\circ, \quad 34^\circ + 146^\circ = 180^\circ, \quad 146^\circ = 146^\circ

Answer

The missing measures are mโˆ 2=56โˆ˜m\angle 2 = 56^\circ, mโˆ 3=146โˆ˜m\angle 3 = 146^\circ, and mโˆ 4=146โˆ˜m\angle 4 = 146^\circ.

Sometimes an angle measure is written with a variable. Here xx stands for an unknown number, and a measure of (2x+8)โˆ˜(2x + 8)^\circ means 2x+82x + 8 degrees. Only values of xx that make every angle measure positive can work. In these equations every number counts degrees, so you can leave the degree sign off until you state a measure.

To solve, do the same thing to both sides. Adding or subtracting the same number keeps an equation true, and so does dividing both sides by the same nonzero number. Finding xx is not the end. Put its value into each expression to get the angle measures. Then check them against every stated fact.

Worked example

Complementary angles with a variable

โˆ P\angle P and โˆ Q\angle Q are complementary, with mโˆ P=(2x+8)โˆ˜m\angle P = (2x + 8)^\circ and mโˆ Q=(3x+2)โˆ˜m\angle Q = (3x + 2)^\circ. Find both angle measures.

  1. Complementary angles have measures that add to 9090 degrees. Add the two expressions and set the sum equal to 9090.

    (2x+8)+(3x+2)=90(2x + 8) + (3x + 2) = 90
  2. Combine like terms on the left. Add the xx-terms, 2x+3x=5x2x + 3x = 5x, and add the plain numbers, 8+2=108 + 2 = 10. This rewrites the left side without changing its value.

    5x+10=905x + 10 = 90
  3. Subtract 1010 from both sides. Then divide both sides by 55, which is not zero. Each move does the same thing to both sides, so the equation stays true.

    5x=80โ‡’x=165x = 80 \quad\Rightarrow\quad x = 16
  4. Put x=16x = 16 into each expression, because the expressions give the measures. So mโˆ P=40โˆ˜m\angle P = 40^\circ and mโˆ Q=50โˆ˜m\angle Q = 50^\circ.

    2(16)+8=32+8=40,3(16)+2=48+2=502(16) + 8 = 32 + 8 = 40, \quad 3(16) + 2 = 48 + 2 = 50
  5. Check: both measures are positive, and they add to 90โˆ˜90^\circ, as complementary angles must.

    40โˆ˜+50โˆ˜=90โˆ˜40^\circ + 50^\circ = 90^\circ

Answer

The measures are mโˆ P=40โˆ˜m\angle P = 40^\circ and mโˆ Q=50โˆ˜m\angle Q = 50^\circ.

Worked example

Vertical angles, then a supplementary pair

Two lines cross at point OO. You are told that โˆ 1\angle 1 and โˆ 3\angle 3 are vertical angles, with mโˆ 1=(5xโˆ’8)โˆ˜m\angle 1 = (5x - 8)^\circ and mโˆ 3=(3x+22)โˆ˜m\angle 3 = (3x + 22)^\circ, and that โˆ 1\angle 1 and โˆ 2\angle 2 are supplementary. Find mโˆ 1m\angle 1, mโˆ 3m\angle 3, and mโˆ 2m\angle 2.

  1. Vertical angles have equal measures, so set the two expressions equal. The relationship itself gives no number of degrees. The numbers in this equation come from the expressions.

    5xโˆ’8=3x+225x - 8 = 3x + 22
  2. Subtract 3x3x from both sides to gather the xx-terms on the left. Then add 88 to both sides. Both moves do the same thing to both sides, so the equation stays true.

    2xโˆ’8=22โ‡’2x=302x - 8 = 22 \quad\Rightarrow\quad 2x = 30
  3. Divide both sides by 22. Dividing both sides by the same nonzero number keeps the equation true.

    x=15x = 15
  4. Put x=15x = 15 into both expressions, because they give the two measures. Both give 6767, so the vertical angles are equal, as they must be: mโˆ 1=mโˆ 3=67โˆ˜m\angle 1 = m\angle 3 = 67^\circ.

    5(15)โˆ’8=75โˆ’8=67,3(15)+22=45+22=675(15) - 8 = 75 - 8 = 67, \quad 3(15) + 22 = 45 + 22 = 67
  5. Now use the supplementary fact: the measures of โˆ 1\angle 1 and โˆ 2\angle 2 add to 180โˆ˜180^\circ. Subtract 67โˆ˜67^\circ from both sides.

    67โˆ˜+mโˆ 2=180โˆ˜โ‡’mโˆ 2=180โˆ˜โˆ’67โˆ˜=113โˆ˜67^\circ + m\angle 2 = 180^\circ \quad\Rightarrow\quad m\angle 2 = 180^\circ - 67^\circ = 113^\circ
  6. Check every fact. All three measures are positive, the vertical pair is equal, and the supplementary pair adds to 180โˆ˜180^\circ.

    67โˆ˜=67โˆ˜,67โˆ˜+113โˆ˜=180โˆ˜67^\circ = 67^\circ, \quad 67^\circ + 113^\circ = 180^\circ

Answer

The measures are mโˆ 1=67โˆ˜m\angle 1 = 67^\circ, mโˆ 3=67โˆ˜m\angle 3 = 67^\circ, and mโˆ 2=113โˆ˜m\angle 2 = 113^\circ.

To find an error in someone's work, start at the end. Put their angle measures into every stated fact. If any fact fails, something went wrong. Then test the work from the top:

  • Does the first equation say exactly what the stated relationship gives?
  • Does each later line follow correctly from the one before?

The first line that fails is the error. Fix it, redo the work from that point, and check the new measures against every fact.

Worked example

Find and fix the error

โˆ ABD\angle ABD and โˆ DBC\angle DBC are adjacent, sharing vertex BB and side BDBD. Together they form โˆ ABC\angle ABC, and mโˆ ABC=120โˆ˜m\angle ABC = 120^\circ. Also, mโˆ ABD=(4x+6)โˆ˜m\angle ABD = (4x + 6)^\circ and mโˆ DBC=(2x+12)โˆ˜m\angle DBC = (2x + 12)^\circ. A student wrote (4x+6)+(2x+12)=180(4x + 6) + (2x + 12) = 180, then 6x+18=1806x + 18 = 180, 6x=1626x = 162, and x=27x = 27. The student answered mโˆ ABD=114โˆ˜m\angle ABD = 114^\circ and mโˆ DBC=66โˆ˜m\angle DBC = 66^\circ. Find the error and correct it.

  1. Start at the end and test the student's measures against the stated facts. The parts should add to the stated whole, 120โˆ˜120^\circ. They add to 180โˆ˜180^\circ instead, so something went wrong.

    114โˆ˜+66โˆ˜=180โˆ˜โ‰ 120โˆ˜114^\circ + 66^\circ = 180^\circ \neq 120^\circ
  2. Now test the work from the top. Each algebra line follows correctly from the one before, and x=27x = 27 does give the student's measures. So the error is the first equation. The student set the sum equal to 180180 as if the angles were supplementary, which was never stated. Being adjacent gives no equation by itself. The sum must come from the stated whole, 120โˆ˜120^\circ.

    4(27)+6=108+6=114,2(27)+12=54+12=664(27) + 6 = 108 + 6 = 114, \quad 2(27) + 12 = 54 + 12 = 66
  3. Write the equation the facts do give: the two parts add to the stated whole.

    (4x+6)+(2x+12)=120(4x + 6) + (2x + 12) = 120
  4. Combine like terms and subtract 1818 from both sides. Then divide both sides by 66, which is not zero. Each move keeps the equation true.

    6x+18=120โ‡’6x=102โ‡’x=176x + 18 = 120 \quad\Rightarrow\quad 6x = 102 \quad\Rightarrow\quad x = 17
  5. Put x=17x = 17 into each expression, because the expressions give the two measures.

    4(17)+6=68+6=74,2(17)+12=34+12=464(17) + 6 = 68 + 6 = 74, \quad 2(17) + 12 = 34 + 12 = 46
  6. Check: both measures are positive, and the parts add to the stated whole.

    74โˆ˜+46โˆ˜=120โˆ˜74^\circ + 46^\circ = 120^\circ

Answer

The error is the first equation, which used 180โˆ˜180^\circ instead of the stated whole, 120โˆ˜120^\circ. The correct measures are mโˆ ABD=74โˆ˜m\angle ABD = 74^\circ and mโˆ DBC=46โˆ˜m\angle DBC = 46^\circ.

Takeaway: each stated fact tells you exactly what you may write. Complementary measures add to 90โˆ˜90^\circ, and supplementary measures add to 180โˆ˜180^\circ. Vertical angles have equal measures. Adjacent angles give an equation only when the whole angle they fill has a stated measure. Write the equation the facts give, solve it, find each angle measure, and check every measure against every fact. That same check is how you find and fix errors.

Next, you will find lengths and measures of bisected segments and angles, which are segments and angles split into two equal parts.